How to resolve the algorithm Random numbers step by step in the Ruby programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Random numbers step by step in the Ruby programming language

Table of Contents

Problem Statement

Generate a collection filled with   1000   normally distributed random (or pseudo-random) numbers with a mean of   1.0   and a   standard deviation   of   0.5 Many libraries only generate uniformly distributed random numbers. If so, you may use one of these algorithms.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Random numbers step by step in the Ruby programming language

The provided Ruby code generates an array of 1000 elements, each of which is a random number following a normal distribution with a mean of 1 and a standard deviation of 1. Here is a breakdown of the code:

Array.new(1000): This creates a new array with 1000 elements. The contents of the array are specified by the block that follows. 1 + Math.sqrt(-2 * Math.log(rand)) * Math.cos(2 * Math::PI * rand): This is the formula used to generate each element of the array. 1: This is the mean of the distribution. Math.sqrt(-2 * Math.log(rand)): This generates a random number from a standard normal distribution. Math.cos(2 * Math::PI * rand): This generates a random angle from a uniform distribution on the interval [0, 2π). The combination of these two terms produces a random number from a normal distribution with a mean of 1 and a standard deviation of 1. The result is stored in each element of the newly created array.

Source code in the ruby programming language

Array.new(1000) { 1 + Math.sqrt(-2 * Math.log(rand)) * Math.cos(2 * Math::PI * rand) }


  

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