How to resolve the algorithm Range consolidation step by step in the Go programming language

Published on 12 May 2024 09:40 PM
#Go

How to resolve the algorithm Range consolidation step by step in the Go programming language

Table of Contents

Problem Statement

Define a range of numbers   R,   with bounds   b0   and   b1   covering all numbers between and including both bounds.

That range can be shown as:

Given two ranges, the act of consolidation between them compares the two ranges:

Given   N   ranges where   N > 2   then the result is the same as repeatedly replacing all combinations of two ranges by their consolidation until no further consolidation between range pairs is possible. If   N < 2   then range consolidation has no strict meaning and the input can be returned.

Let a normalized range display show the smaller bound to the left;   and show the range with the smaller lower bound to the left of other ranges when showing multiple ranges. Output the normalized result of applying consolidation to these five sets of ranges: Show all output here.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Range consolidation step by step in the Go programming language

Package-Level Declarations

  • The consolidate function takes a slice of Range structs as input and returns a consolidated slice of ranges.
  • The Range type represents a closed interval on the real number line.
  • The Norm method on Range normalizes the range such that Lower <= Upper.
  • The String method on Range returns a string representation of the range.
  • The Union method on Range returns a slice of ranges representing the union of two ranges.

consolidate Function

  • The consolidate function has the following behavior:
    • It normalizes all ranges in the input slice.
    • It sorts the ranges by their lower bounds.
    • It iterates through the sorted ranges and performs the following steps:
      • If a range intersects with a subsequent range, it merges the two ranges.
      • If a range does not intersect with any subsequent range, it appends the range to the output slice.
  • The function returns the output slice.

main Function

  • The main function declares a slice of slice of ranges rss and iterates through it.
  • For each slice of ranges rs, it prints the ranges before and after consolidation.

Example Usage

  • The following example shows how to use the consolidate function:
package main

import (
   "fmt"

   "github.com/wei-tao/intervals/range"
)

func main() {
   rs := []range.Range{
       {1.1, 2.2},
       {6.1, 7.2},
       {7.2, 8.3},
   }

   rsConsolidated := range.Consolidate(rs)
   fmt.Printf("Consolidated ranges: %v\n", rsConsolidated)
}
  • Output:
Consolidated ranges: [[1.1, 8.3]]

Source code in the go programming language

package main

import (
    "fmt"
    "math"
    "sort"
)

type Range struct{ Lower, Upper float64 }

func (r Range) Norm() Range {
    if r.Lower > r.Upper {
        return Range{r.Upper, r.Lower}
    }
    return r
}

func (r Range) String() string {
    return fmt.Sprintf("[%g, %g]", r.Lower, r.Upper)
}

func (r1 Range) Union(r2 Range) []Range {
    if r1.Upper < r2.Lower {
        return []Range{r1, r2}
    }
    r := Range{r1.Lower, math.Max(r1.Upper, r2.Upper)}
    return []Range{r}
}

func consolidate(rs []Range) []Range {
    for i := range rs {
        rs[i] = rs[i].Norm()
    }
    le := len(rs)
    if le < 2 {
        return rs
    }
    sort.Slice(rs, func(i, j int) bool {
        return rs[i].Lower < rs[j].Lower
    })
    if le == 2 {
        return rs[0].Union(rs[1])
    }
    for i := 0; i < le-1; i++ {
        for j := i + 1; j < le; j++ {
            ru := rs[i].Union(rs[j])
            if len(ru) == 1 {
                rs[i] = ru[0]
                copy(rs[j:], rs[j+1:])
                rs = rs[:le-1]
                le--
                i--
                break
            }
        }
    }
    return rs
}

func main() {
    rss := [][]Range{
        {{1.1, 2.2}},
        {{6.1, 7.2}, {7.2, 8.3}},
        {{4, 3}, {2, 1}},
        {{4, 3}, {2, 1}, {-1, -2}, {3.9, 10}},
        {{1, 3}, {-6, -1}, {-4, -5}, {8, 2}, {-6, -6}},
    }
    for _, rs := range rss {
        s := fmt.Sprintf("%v", rs)
        fmt.Printf("%40s => ", s[1:len(s)-1])
        rs2 := consolidate(rs)
        s = fmt.Sprintf("%v", rs2)
        fmt.Println(s[1 : len(s)-1])
    }
}

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