How to resolve the algorithm Range extraction step by step in the C++ programming language
Published on 7 June 2024 03:52 AM
How to resolve the algorithm Range extraction step by step in the C++ programming language
Table of Contents
Problem Statement
A format for expressing an ordered list of integers is to use a comma separated list of either Example The list of integers: Is accurately expressed by the range expression: (And vice-versa).
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Range extraction step by step in the C++ programming language
The provided C++ code defines a function to extract and print ranges of consecutive numbers from an input sequence.
Here's a detailed explanation:
-
extract_ranges()
Function:- Input Parameters:
begin
: An input iterator pointing to the start of the sequence.end
: An input iterator pointing to the end of the sequence.os
: An output stream (e.g.,std::cout
) to which the extracted ranges will be printed.
- Purpose: To extract and print consecutive number ranges from the input sequence.
- Input Parameters:
-
Main Function:
-
It defines an integer array
data[]
containing a sequence of numbers. -
It calls the
extract_ranges()
function with the address of thedata
array as thebegin
iterator, a pointer to the end of the array as theend
iterator, andstd::cout
as the output stream.
-
-
end()
Function (Helper Function):- This function is used internally by
extract_ranges()
. It takes an arrayarray
and its sizen
and returns a pointer to the element after the last element in the array (array + n
).
- This function is used internally by
-
Implementation of
extract_ranges()
:- It initializes the current number (
current
) to the value at the beginning of the sequence (*begin
) and prints it. - It initializes a count variable (
count
) to 1, indicating that a single number has been encountered so far. - It enters a loop that continues until the end of the sequence (
begin != end
). - Inside the loop, it checks the next number (
next
) in the sequence. - If
next
is one greater than the current number, it increments the count. - If
next
is not one greater than the current number, it prints the current range as follows:- If
count
is greater than 2, it prints a hyphen (-
) to indicate a range of numbers. - If
count
is 2 or less, it prints a comma ( - It prints the current number and the next number, separated by a comma if
count
is greater than 1. - It resets the count to 1.
- If
- After processing all numbers in the sequence, it checks the final count and prints the last range accordingly.
- It initializes the current number (
-
Output:
- The provided input sequence
data
will produce the following output:0,1,2,4-8,11-12,14-25,27-33,35-39
- The provided input sequence
Source code in the cpp programming language
#include <iostream>
#include <iterator>
#include <cstddef>
template<typename InIter>
void extract_ranges(InIter begin, InIter end, std::ostream& os)
{
if (begin == end)
return;
int current = *begin++;
os << current;
int count = 1;
while (begin != end)
{
int next = *begin++;
if (next == current+1)
++count;
else
{
if (count > 2)
os << '-';
else
os << ',';
if (count > 1)
os << current << ',';
os << next;
count = 1;
}
current = next;
}
if (count > 1)
os << (count > 2? '-' : ',') << current;
}
template<typename T, std::size_t n>
T* end(T (&array)[n])
{
return array+n;
}
int main()
{
int data[] = { 0, 1, 2, 4, 6, 7, 8, 11, 12, 14,
15, 16, 17, 18, 19, 20, 21, 22, 23, 24,
25, 27, 28, 29, 30, 31, 32, 33, 35, 36,
37, 38, 39 };
extract_ranges(data, end(data), std::cout);
std::cout << std::endl;
}
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