How to resolve the algorithm Rate counter step by step in the BBC BASIC programming language

Published on 12 May 2024 09:40 PM
#Bbc basic

How to resolve the algorithm Rate counter step by step in the BBC BASIC programming language

Table of Contents

Problem Statement

Of interest is the code that performs the actual measurements. Any other code (such as job implementation or dispatching) that is required to demonstrate the rate tracking is helpful, but not the focus. Multiple approaches are allowed (even preferable), so long as they can accomplish these goals: Be aware of the precision and accuracy limitations of your timing mechanisms, and document them if you can. See also: System time, Time a function

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Rate counter step by step in the BBC BASIC programming language

Source code in the bbc programming language

      PRINT "Method 1: Calculate reciprocal of elapsed time:"
      FOR trial% = 1 TO 3
        start% = TIME
        PROCtasktomeasure
        finish% = TIME
        PRINT "Rate = "; 100 / (finish%-start%) " per second"
      NEXT trial%
      
      PRINT '"Method 2: Count completed tasks in one second:"
      FOR trial% = 1 TO 3
        runs% = 0
        finish% = TIME + 100
        REPEAT
          PROCtasktomeasure
          IF TIME < finish% runs% += 1
        UNTIL TIME >= finish%
        PRINT "Rate = "; runs% " per second"
      NEXT trial%
      END
      
      REM This is an example, replace with the task you want to measure
      DEF PROCtasktomeasure
      LOCAL i%
      FOR i% = 1 TO 1000000
      NEXT
      ENDPROC

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