How to resolve the algorithm Reverse words in a string step by step in the AutoHotkey programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Reverse words in a string step by step in the AutoHotkey programming language

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Problem Statement

Reverse the order of all tokens in each of a number of strings and display the result;   the order of characters within a token should not be modified.

Hey you, Bub!   would be shown reversed as:   Bub! you, Hey

Tokens are any non-space characters separated by spaces (formally, white-space);   the visible punctuation form part of the word within which it is located and should not be modified. You may assume that there are no significant non-visible characters in the input.   Multiple or superfluous spaces may be compressed into a single space. Some strings have no tokens, so an empty string   (or one just containing spaces)   would be the result. Display the strings in order   (1st, 2nd, 3rd, ···),   and one string per line. (You can consider the ten strings as ten lines, and the tokens as words.)

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Reverse words in a string step by step in the AutoHotkey programming language

Source code in the autohotkey programming language

Data := "
(Join`r`n
---------- Ice and Fire ------------

fire, in end will world the say Some
ice. in say Some
desire of tasted I've what From
fire. favor who those with hold I

... elided paragraph last ...

Frost Robert ----------------------- 
)"

Loop, Parse, Data, `n, `r
{
	Loop, Parse, A_LoopField, % A_Space
		Line := A_LoopField " " Line
	Output .= Line "`n", Line := ""
}
MsgBox, % RTrim(Output, "`n")


  

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