Problem Statement

Reverse the order of all tokens in each of a number of strings and display the result;   the order of characters within a token should not be modified.

Hey you, Bub!   would be shown reversed as:   Bub! you, Hey

Tokens are any non-space characters separated by spaces (formally, white-space);   the visible punctuation form part of the word within which it is located and should not be modified. You may assume that there are no significant non-visible characters in the input.   Multiple or superfluous spaces may be compressed into a single space. Some strings have no tokens, so an empty string   (or one just containing spaces)   would be the result. Display the strings in order   (1st, 2nd, 3rd, ···),   and one string per line. (You can consider the ten strings as ten lines, and the tokens as words.)

Let's start with the solution:

defmodule RC do
  def reverse_words(txt) do
    txt |> String.split("\n")       # split lines
        |> Enum.map(&(              # in each line
             &1 |> String.split       # split words
                |> Enum.reverse       # reverse words
                |> Enum.join(" ")))   # rejoin words
        |> Enum.join("\n")          # rejoin lines
  end 
end


txt = """
---------- Ice and Fire ------------
                                    
fire, in end will world the say Some
ice. in say Some                    
desire of tasted I've what From     
fire. favor who those with hold I   
                                    
... elided paragraph last ...       
                                    
Frost Robert -----------------------
"""

IO.puts RC.reverse_words(txt)