How to resolve the algorithm Reverse words in a string step by step in the Pascal programming language
How to resolve the algorithm Reverse words in a string step by step in the Pascal programming language
Table of Contents
Problem Statement
Reverse the order of all tokens in each of a number of strings and display the result; the order of characters within a token should not be modified.
Hey you, Bub! would be shown reversed as: Bub! you, Hey
Tokens are any non-space characters separated by spaces (formally, white-space); the visible punctuation form part of the word within which it is located and should not be modified. You may assume that there are no significant non-visible characters in the input. Multiple or superfluous spaces may be compressed into a single space. Some strings have no tokens, so an empty string (or one just containing spaces) would be the result. Display the strings in order (1st, 2nd, 3rd, ···), and one string per line. (You can consider the ten strings as ten lines, and the tokens as words.)
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Reverse words in a string step by step in the Pascal programming language
Source code in the pascal programming language
program Reverse_words(Output);
{$H+}
const
nl = chr(10); // Linefeed
sp = chr(32); // Space
TXT =
'---------- Ice and Fire -----------'+nl+
nl+
'fire, in end will world the say Some'+nl+
'ice. in say Some'+nl+
'desire of tasted I''ve what From'+nl+
'fire. favor who those with hold I'+nl+
nl+
'... elided paragraph last ...'+nl+
nl+
'Frost Robert -----------------------'+nl;
var
I : integer;
ew, lw : ansistring;
c : char;
function addW : ansistring;
var r : ansistring = '';
begin
r := ew + sp + lw;
ew := '';
addW := r
end;
begin
ew := '';
lw := '';
for I := 1 to strlen(TXT) do
begin
c := TXT[I];
case c of
sp : lw := addW;
nl : begin writeln(addW); lw := '' end;
else ew := ew + c
end;
end;
readln;
end.
program reverse_words;
{$mode objfpc}{$h+}
uses
SysUtils;
function Reverse(a: TStringArray): TStringArray;
var
I, J: SizeInt;
t: Pointer;
begin
I := 0;
J := High(a);
while I < J do begin
t := Pointer(a[I]);
Pointer(a[I]) := Pointer(a[J]);
Pointer(a[J]) := t;
Inc(I);
Dec(J);
end;
Result := a;
end;
const
Input =
'---------- Ice and Fire -----------' + LineEnding +
'' + LineEnding +
'fire, in end will world the say Some' + LineEnding +
'ice. in say Some' + LineEnding +
'desire of tasted I''ve what From' + LineEnding +
'fire. favor who those with hold I' + LineEnding +
'' + LineEnding +
'... elided paragraph last ...' + LineEnding +
'' + LineEnding +
'Frost Robert -----------------------' + LineEnding;
var
Line: string;
begin
for Line in Input.Split([LineEnding], TStringSplitOptions.ExcludeLastEmpty) do
WriteLn(string.Join(' ', Reverse(Line.Split([' ']))));
end.
You may also check:How to resolve the algorithm Metallic ratios step by step in the Nim programming language
You may also check:How to resolve the algorithm Sequence of primorial primes step by step in the Ring programming language
You may also check:How to resolve the algorithm Universal Turing machine step by step in the JavaScript programming language
You may also check:How to resolve the algorithm Simple windowed application step by step in the Fantom programming language
You may also check:How to resolve the algorithm Singly-linked list/Element insertion step by step in the Tcl programming language