How to resolve the algorithm Riordan numbers step by step in the Perl programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Riordan numbers step by step in the Perl programming language

Table of Contents

Problem Statement

Riordan numbers show up in several places in set theory. They are closely related to Motzkin numbers, and may be used to derive them. Riordan numbers comprise the sequence a where: There are other generating functions, and you are free to use one most convenient for your language.

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Step by Step solution about How to resolve the algorithm Riordan numbers step by step in the Perl programming language

Source code in the perl programming language

use v5.36;
use bigint try => 'GMP';
use experimental <builtin for_list>;
use List::Util 'max';
use List::Lazy 'lazy_list';
use Lingua::EN::Numbers qw(num2en_ordinal);

sub abbr ($d) { my $l = length $d; $l < 41 ? $d : substr($d,0,20) . '..' . substr($d,-20) . " ($l digits)" }
sub comma { reverse ((reverse shift) =~ s/(.{3})/$1,/gr) =~ s/^,//r }
sub table ($c, @V) { my $t = $c * (my $w = 2 + max map { length } @V); ( sprintf( ('%'.$w.'s')x@V, @V) ) =~ s/.{1,$t}\K/\n/gr }

my @riordan;
my $riordan_lazy = lazy_list { state @r = (1,0); state $n = 1; $n++; push @r, ($n-1) * (2*$r[1] + 3*$r[0]) / ($n+1) ; shift @r };
push @riordan, $riordan_lazy->next() for 1..1e4;

say 'First thirty-two Riordan numbers:';
say table 4, map { comma $_ } @riordan[0..31];
say 'The ' . num2en_ordinal($_) . ': ' . abbr $riordan[$_ - 1] for 1e3, 1e4;


  

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