How to resolve the algorithm Rock-paper-scissors step by step in the UNIX Shell programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Rock-paper-scissors step by step in the UNIX Shell programming language

Table of Contents

Problem Statement

Implement the classic children's game Rock-paper-scissors, as well as a simple predictive   AI   (artificial intelligence)   player. Rock Paper Scissors is a two player game. Each player chooses one of rock, paper or scissors, without knowing the other player's choice. The winner is decided by a set of rules:

If both players choose the same thing, there is no winner for that round. For this task, the computer will be one of the players. The operator will select Rock, Paper or Scissors and the computer will keep a record of the choice frequency, and use that information to make a weighted random choice in an attempt to defeat its opponent.

Support additional choices   additional weapons.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Rock-paper-scissors step by step in the UNIX Shell programming language

Source code in the unix programming language

#!/bin/bash
choices=(rock paper scissors)

# comparison function, works like Perl 
# winner x y =  2 if y beats x, 1 if x beats 1, 0 if it's a tie
winner() {
  local left="$1" right="$2"
  echo $(( (3 + left - right) % 3 ))
}


human_counts=(1 1 1)
human_count=3
computer_counts=(0 0 0)
games=0 human=0 computer=0

PS3="What do you throw? "
while true; do 
  select choice in rock paper scissors quit; do
    if [ -z "$choice" ]; then choice="$REPLY"; fi
    if [ "$choice" = "quit" ]; then
      break 2
    fi
    for (( h=0; h<${#choices[@]}; ++h )); do
      if [ "${choices[h]}" = "$choice" ]; then
        break
      fi
    done
    if (( h < 3 )); then
      break
    fi
    echo "Unrecognized choice.  Try again!"
  done

  let n=RANDOM%human_count
  for (( c=0; c<${#human_counts[@]}; ++c )); do
    let n-=${human_counts[c]}
    if (( n < 0 )); then
       break
    fi
  done
  let computer_counts[c]+=1
  echo 
  echo "You chose ${choices[h]^^}"
  echo "I chose ${choices[c]^^}"
  w="$(winner "$c" "$h")"
  case "$w" in
     2) echo "YOU WIN!"; let human+=1;;
     0) echo "TIE!";;
     1) echo "I WIN!"; let computer+=1;;
     *) echo "winner returned weird result '$w'";;
  esac
  echo
  let games+=1
  (( human_counts[(h+1)%3]+=1, human_count+=1 ))
done

echo 
echo "We played $games games.  You won $human, and I won $computer."
for (( i=0; i<3; ++i )); do
  echo "You picked ${choices[i]} $(( human_counts[ (i+1)%3 ] - 1 )) times."
  echo "I picked ${choices[i]} $(( computer_counts[i] )) times."
done


  

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