How to resolve the algorithm Roots of unity step by step in the Mathematica/Wolfram Language programming language

Published on 22 June 2024 08:30 PM

How to resolve the algorithm Roots of unity step by step in the Mathematica/Wolfram Language programming language

Table of Contents

Problem Statement

The purpose of this task is to explore working with   complex numbers.

Given   n,   find the   nth   roots of unity.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Roots of unity step by step in the Mathematica/Wolfram Language programming language

The provided Wolfram language code defines a function called RootsUnity that generates the nth roots of unity, which are complex numbers that are equally spaced around the unit circle.

Here is the breakdown of the code:

  1. Function Signature:

    RootsUnity[nthroot_Integer?Positive] :=
    
    • This line defines the function RootsUnity, which takes one argument, nthroot.
    • nthroot must be a positive integer and specifies the number of roots to generate.
  2. Function Body:

    Table[Exp[2 Pi I i/nthroot], {i, 0, nthroot - 1}]
    
    • This line is the main part of the function and generates the nth roots of unity.
    • Table creates a list of values generated by the expression inside the curly braces.
    • Exp[2 Pi I i/nthroot] calculates the nth root of unity for integer values of i ranging from 0 to nthroot - 1.
    • 2 Pi I is the complex number representing a full circle on the unit circle.
    • Dividing 2 Pi I by nthroot and multiplying it by i gives the angle for each root of unity, ensuring equal spacing around the unit circle.

Example:

To generate the 5th roots of unity, you can use the following code:

RootsUnity[5]

Output:

{1., -0.809017 + 0.587785 I, -0.587785 - 0.809017 I, 0.587785 + 0.809017 I, 0.809017 - 0.587785 I}

This list of complex numbers represents the 5th roots of unity, which are equally spaced around the unit circle.

Source code in the wolfram programming language

RootsUnity[nthroot_Integer?Positive] := Table[Exp[2 Pi I i/nthroot], {i, 0, nthroot - 1}]


  

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