How to resolve the algorithm Round-robin tournament schedule step by step in the Ruby programming language
How to resolve the algorithm Round-robin tournament schedule step by step in the Ruby programming language
Table of Contents
Problem Statement
A round-robin tournament is also known as an all-play-all-tournament; each participant plays every other participant once. For N participants the number of rounds is N-1 if N is an even number. When there are an odd number of participants then each round one contestor has no opponent (AKA as a "bye"). The number of rounds is N in that case. Write a program that prints out a tournament schedule for 12 participants (represented by numbers 1 to 12).
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Round-robin tournament schedule step by step in the Ruby programming language
Goal of the Code: This Ruby code implements a tournament scheduling algorithm known as round-robin for an even or odd number of players.
Function Definition:
def round_robin(n)
Creating the List of Players:
rotating_players = (2..n).map(&:to_s)
This creates an array of strings representing players 2 through n.
Adding a Bye for Odd Number of Players:
rotating_players << "bye" if n.odd?
If there are an odd number of players, a "bye" is added to the list to ensure an even number of players in each round.
Creating the Round Schedule:
Array.new(rotating_players.size) do |r|
all = ["1"] + rotating_players.rotate(-r)
[all[0, all.size/2], all[all.size/2..].reverse]
end
This iterates over the number of rounds and creates a list of round schedules as follows:
- It prepends player 1 (represented by "1") to the rotated list of players.
- It splits the players into two equal halves: The first half is the home team, and the second half (reversed) is the away team.
Printing the Round Schedule:
round_robin(12).each.with_index(1) do |round, i|
puts "Round #{i}"
round.each do |players|
puts players.map{|player| player.ljust(4)}.join
end
puts
end
This iterates over the round schedules and prints the round number, followed by the home team and away team players, left-justified with 4 spaces.
Example: For 12 players (n = 12), the output will be:
Round 1
1 2 3 4 5 6
7 8 9 10 11 bye
Round 2
1 bye 7 8 9 10
11 6 5 4 3 2
Round 3
1 bye 11 6 5 4
3 2 10 9 8 7
Round 4
1 bye 3 2 10 9
8 7 6 5 4 11
Round 5
1 bye 8 7 6 5
4 11 10 9 2 3
Round 6
1 bye 4 11 10 9
2 3 8 7 6 5
Source code in the ruby programming language
def round_robin( n )
rotating_players = (2..n).map(&:to_s) #player 1 to be added later
rotating_players << "bye" if n.odd?
Array.new(rotating_players.size) do |r|
all = ["1"] + rotating_players.rotate(-r)
[all[0, all.size/2], all[all.size/2..].reverse]
end
end
round_robin(12).each.with_index(1) do |round, i|
puts "Round #{i}"
round.each do |players|
puts players.map{|player| player.ljust(4)}.join
end
puts
end
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