Problem Statement

Five sailors are shipwrecked on an island and collect a large pile of coconuts during the day. That night the first sailor wakes up and decides to take his first share early so tries to divide the pile of coconuts equally into five piles but finds that there is one coconut left over, so he tosses it to a monkey and then hides "his" one of the five equally sized piles of coconuts and pushes the other four piles together to form a single visible pile of coconuts again and goes to bed. To cut a long story short, each of the sailors in turn gets up once during the night and performs the same actions of dividing the coconut pile into five, finding that one coconut is left over and giving that single remainder coconut to the monkey. In the morning (after the surreptitious and separate action of each of the five sailors during the night), the remaining coconuts are divided into five equal piles for each of the sailors, whereupon it is found that the pile of coconuts divides equally amongst the sailors with no remainder. (Nothing for the monkey in the morning.)

Let's start with the solution:

var coconuts = 11
for (ns in 2..9) {
    var hidden = List.filled(ns, 0)
    coconuts = (coconuts/ns).floor * ns + 1
    while (true) {
        var nc = coconuts
        var outer = false
        for (s in 1..ns) {
            if (nc%ns == 1) {
                hidden[s-1] = (nc/ns).floor
                nc = nc - hidden[s-1] - 1
                if (s == ns && nc%ns == 0) {
                    System.print("%(ns) sailors require a minimum of %(coconuts) coconuts")
                    for (t in 1..ns) System.print("\tSailor %(t) hides %(hidden[t-1])")
                    System.print("\tThe monkey gets %(ns)")
                    System.print("\tFinally, each sailor takes %((nc/ns).floor)\n")
                    outer = true
                    break
                }
            } else {
                break
            }
        }
        if (outer) break
        coconuts = coconuts + ns
    }
}