How to resolve the algorithm Semiprime step by step in the C# programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Semiprime step by step in the C# programming language

Table of Contents

Problem Statement

Semiprime numbers are natural numbers that are products of exactly two (possibly equal) prime numbers.

Semiprimes   are also known as:

(This particular number was chosen as the length of the Arecibo message).

Write a function determining whether a given number is semiprime.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Semiprime step by step in the C# programming language

The code snippet is a C# program that tests if a number is semiprime. A semiprime number is a natural number that is the product of two prime numbers. The program tests numbers from 0 to 49 and prints the result to the console.

The isSemiPrime function takes an integer as input and returns true if the input is semiprime, and false otherwise. The function works by iterating over all the numbers from 2 to the square root of the input, and checking if the input is divisible by any of these numbers. If the input is divisible by a number, then the function divides the input by that number and increments a counter. If the counter reaches 2, then the input is semiprime and the function returns true. Otherwise, the function returns false.

The main function of the program simply calls the isSemiPrime function for each number from 0 to 49 and prints the result to the console.

Source code in the csharp programming language

static void Main(string[] args)
{
    //test some numbers
    for (int i = 0; i < 50; i++)
    {
        Console.WriteLine("{0}\t{1} ", i,isSemiPrime(i));
    }
    Console.ReadLine();
}

//returns true or false depending if input was considered semiprime
private static bool isSemiPrime(int c)
{
    int a = 2, b = 0;
    while (b < 3 && c != 1)
    {
        if ((c % a) == 0)
        {
            c /= a;
            b++;
        }
        else
        {
            a++;
        };
    }
    return b == 2;
}


  

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