Step by Step solution about How to resolve the algorithm Semordnilap step by step in the Ruby programming language

Both snippets of code are in Ruby and they solve the problem of finding words that are semordnilaps, which means that they are the same when reversed.

The first snippet reads the file "unixdict.txt" which is a list of words and removes the newline characters from each word. Then it reverses each word and sorts the list of reversed words. It then iterates over the reversed words and checks if the current word is greater than the next word in the original list of words and if the current word is less than its reverse. If both conditions are met, the word is a semordnilap and is added to the result list. Finally, the first 5 semordnilaps are printed to the console.

The second snippet also reads the file "unixdict.txt" and groups the words by their minimum value between the word and its reverse. Then it selects the groups that have a size of 2, which means that they contain a word and its reverse. Finally, the first 5 semordnilaps are printed to the console.

dict = File.readlines("unixdict.txt").collect(&:strip)
i = 0
res = dict.collect(&:reverse).sort.select do |z| 
  i += 1  while z > dict[i] and i < dict.length-1
  z == dict[i] and z < z.reverse
end
puts "There are #{res.length} semordnilaps, of which the following are 5:"
res.take(5).each {|z| puts "#{z}   #{z.reverse}"}


words = File.readlines("unixdict.txt")
            .group_by{|x| [x.strip!, x.reverse].min}
            .values
            .select{|v| v.size==2}
puts "There are #{words.size} semordnilaps, of which the following are 5:"
words.take(5).each {|a,b| puts "#{a}   #{b}"}