How to resolve the algorithm Sequence: smallest number with exactly n divisors step by step in the Nim programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Sequence: smallest number with exactly n divisors step by step in the Nim programming language
Table of Contents
Problem Statement
Calculate the sequence where each term an is the smallest natural number that has exactly n divisors.
Show here, on this page, at least the first 15 terms of the sequence.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Sequence: smallest number with exactly n divisors step by step in the Nim programming language
Source code in the nim programming language
import strformat
const MAX = 15
func countDivisors(n: int): int =
var count = 0
var i = 1
while i * i <= n:
if n mod i == 0:
if i == n div i:
inc count, 1
else:
inc count, 2
inc i
count
var sequence: array[MAX, int]
echo fmt"The first {MAX} terms of the sequence are:"
var i = 1
var n = 0
while n < MAX:
var k = countDivisors(i)
if k <= MAX and sequence[k - 1] == 0:
sequence[k - 1] = i
inc n
inc i
echo sequence
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