How to resolve the algorithm Sequence: smallest number with exactly n divisors step by step in the Python programming language
How to resolve the algorithm Sequence: smallest number with exactly n divisors step by step in the Python programming language
Table of Contents
Problem Statement
Calculate the sequence where each term an is the smallest natural number that has exactly n divisors.
Show here, on this page, at least the first 15 terms of the sequence.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Sequence: smallest number with exactly n divisors step by step in the Python programming language
The Python code you provided is an implementation of the A005179 sequence, which represents the smallest number with exactly n divisors. The code includes two different implementations of the sequence: one using a generator function (sequence
) and the other using a more functional programming approach (a005179
). The code also includes a helper function, divisors
, which computes the divisors of a given number, and several utility functions for working with sequences and numbers (take
, until
, properDivisors
, primeFactors
, and go
).
Here's a detailed explanation of how the code works:
divisors
function:
- This function takes an integer
n
and returns a list of its divisors. - It starts by initializing a list
divs
with the number 1 (which is always a divisor of any number). - Then, it iterates through the numbers from 2 to the square root of
n
(rounded up to the nearest integer). - For each number
ii
, it checks if it evenly dividesn
. If it does, it addsii
andn / ii
to thedivs
list. - Finally, it adds
n
to thedivs
list and returns the set of all unique divisors in the list.
sequence
function:
- This is a generator function that yields the smallest number with exactly
n
divisors, for eachn
in the range [1,max_n
]. - It initializes a variable
n
to 0 and enters a while loop that runs indefinitely. - Inside the loop, it increments
n
by 1. - It then initializes another variable
ii
to 0 and enters a nested while loop. - Inside the nested loop, it increments
ii
by 1. - It computes the divisors of
ii
using thedivisors
function and checks if the length of the divisors list is equal ton
. - If the condition is met, it yields
ii
and breaks out of the nested loop. - The outer while loop continues to iterate, incrementing
n
and repeating the process for the next value ofn
.
a005179
function:
- This is a generator function that yields the A005179 sequence.
- It uses a comprehension to generate the sequence. The comprehension starts with a generator that produces the numbers 1, 2, 3, ... indefinitely.
- It then applies a filter to the generator, which checks if the number
n
(the next number in the sequence) satisfies the condition that it has exactlyn
divisors. The condition is checked using theproperDivisors
function, which returns the proper divisors of a number (excluding the number itself). - The filtered generator is then used to create the sequence, which is yielded by the
a005179
function.
properDivisors
function:
- This function computes the proper divisors of an integer
n
, which are the divisors ofn
excludingn
itself. - It uses a recursive helper function
go
to compute the divisors. Thego
function takes two arguments: a list of divisorsa
and a list of prime factorsx
. - The
go
function first initializes a listqr
with the divisorsa
and the product of the elements inx
. - It then maps the elements of
qr
to a list of products of the elements ina
and the accumulated product of the elements inx
. - The resulting list is sorted and then returned, excluding the last element (which is
n
).
primeFactors
function:
- This function computes the prime factors of an integer
n
. - It uses a recursive helper function
f
to compute the prime factors. Thef
function takes a tupleqr
as an argument, whereqr[0]
is a prime factor andqr[1]
is the quotient ofn
divided by the prime factor. - The
f
function returns a tupleqr
whereqr[0]
is the next prime factor andqr[1]
is the quotient ofn
divided by the next prime factor. - The
f
function is applied recursively until the quotientqr[1]
is less than or equal to the square root ofn
. - The resulting list of prime factors is returned.
take
function:
- This is a utility function that takes a number
n
and a sequencexs
as arguments and returns the prefix ofxs
of lengthn
, orxs
itself ifn
is greater than the length ofxs
.
until
function:
- This is a utility function that takes a predicate function
p
and a functionf
as arguments and returns a function that appliesf
to an initial valuex
untilp(x)
is True. The resulting value ofx
is returned.
The main
function uses the a005179
function to generate the first 15 terms of the A005179 sequence and print them to the console.
Source code in the python programming language
def divisors(n):
divs = [1]
for ii in range(2, int(n ** 0.5) + 3):
if n % ii == 0:
divs.append(ii)
divs.append(int(n / ii))
divs.append(n)
return list(set(divs))
def sequence(max_n=None):
n = 0
while True:
n += 1
ii = 0
if max_n is not None:
if n > max_n:
break
while True:
ii += 1
if len(divisors(ii)) == n:
yield ii
break
if __name__ == '__main__':
for item in sequence(15):
print(item)
'''Smallest number with exactly n divisors'''
from itertools import accumulate, chain, count, groupby, islice, product
from functools import reduce
from math import sqrt, floor
from operator import mul
# a005179 :: () -> [Int]
def a005179():
'''Integer sequence: smallest number with exactly n divisors.'''
return (
next(
x for x in count(1)
if n == 1 + len(properDivisors(x))
) for n in count(1)
)
# --------------------------TEST---------------------------
# main :: IO ()
def main():
'''First 15 terms of a005179'''
print(main.__doc__ + ':\n')
print(
take(15)(
a005179()
)
)
# -------------------------GENERIC-------------------------
# properDivisors :: Int -> [Int]
def properDivisors(n):
'''The ordered divisors of n, excluding n itself.
'''
def go(a, x):
return [a * b for a, b in product(
a,
accumulate(chain([1], x), mul)
)]
return sorted(
reduce(go, [
list(g) for _, g in groupby(primeFactors(n))
], [1])
)[:-1] if 1 < n else []
# primeFactors :: Int -> [Int]
def primeFactors(n):
'''A list of the prime factors of n.
'''
def f(qr):
r = qr[1]
return step(r), 1 + r
def step(x):
return 1 + (x << 2) - ((x >> 1) << 1)
def go(x):
root = floor(sqrt(x))
def p(qr):
q = qr[0]
return root < q or 0 == (x % q)
q = until(p)(f)(
(2 if 0 == x % 2 else 3, 1)
)[0]
return [x] if q > root else [q] + go(x // q)
return go(n)
# take :: Int -> [a] -> [a]
# take :: Int -> String -> String
def take(n):
'''The prefix of xs of length n,
or xs itself if n > length xs.
'''
return lambda xs: (
xs[0:n]
if isinstance(xs, (list, tuple))
else list(islice(xs, n))
)
# until :: (a -> Bool) -> (a -> a) -> a -> a
def until(p):
'''The result of repeatedly applying f until p holds.
The initial seed value is x.
'''
def go(f, x):
v = x
while not p(v):
v = f(v)
return v
return lambda f: lambda x: go(f, x)
# MAIN ---
if __name__ == '__main__':
main()
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