How to resolve the algorithm Short-circuit evaluation step by step in the Nemerle programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Short-circuit evaluation step by step in the Nemerle programming language

Table of Contents

Problem Statement

Assume functions   a   and   b   return boolean values,   and further, the execution of function   b   takes considerable resources without side effects, and is to be minimized. If we needed to compute the conjunction   (and): Then it would be best to not compute the value of   b()   if the value of   a()   is computed as   false,   as the value of   x   can then only ever be   false. Similarly, if we needed to compute the disjunction (or): Then it would be best to not compute the value of   b()   if the value of   a()   is computed as   true,   as the value of   y   can then only ever be   true. Some languages will stop further computation of boolean equations as soon as the result is known, so-called   short-circuit evaluation   of boolean expressions

Create two functions named   a   and   b,   that take and return the same boolean value. The functions should also print their name whenever they are called. Calculate and assign the values of the following equations to a variable in such a way that function   b   is only called when necessary: If the language does not have short-circuit evaluation, this might be achieved with nested     if     statements.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Short-circuit evaluation step by step in the Nemerle programming language

Source code in the nemerle programming language

using System.Console;

class ShortCircuit
{
    public static a(x : bool) : bool
    {
        WriteLine("a");
        x
    }

    public static b(x : bool) : bool
    {
        WriteLine("b");
        x
    }
    
    public static Main() : void
    {
        def t = true;
        def f = false;

        WriteLine("True  && True : {0}", a(t) && b(t));
        WriteLine("True  && False: {0}", a(t) && b(f));
        WriteLine("False && True : {0}", a(f) && b(t));
        WriteLine("False && False: {0}", a(f) && b(f));
        WriteLine("True  || True : {0}", a(t) || b(t)); 
        WriteLine("True  || False: {0}", a(t) || b(f));
        WriteLine("False || True : {0}", a(f) || b(t));
        WriteLine("False || False: {0}", a(f) || b(f));   
    }
}


a
b
True  && True : True
a
b
True  && False: False
a
False && True : False
a
False && False: False
a
True  || True : True
a
True  || False: True
a
b
False || True : True
a
b
False || False: False


  

You may also check:How to resolve the algorithm Peano curve step by step in the Rust programming language
You may also check:How to resolve the algorithm Append a record to the end of a text file step by step in the Sidef programming language
You may also check:How to resolve the algorithm Brownian tree step by step in the Tcl programming language
You may also check:How to resolve the algorithm Calkin-Wilf sequence step by step in the Ruby programming language
You may also check:How to resolve the algorithm Hello world/Line printer step by step in the Common Lisp programming language