How to resolve the algorithm Sierpinski pentagon step by step in the Java programming language
How to resolve the algorithm Sierpinski pentagon step by step in the Java programming language
Table of Contents
Problem Statement
Produce a graphical or ASCII-art representation of a Sierpinski pentagon (aka a Pentaflake) of order 5. Your code should also be able to correctly generate representations of lower orders: 1 to 4.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Sierpinski pentagon step by step in the Java programming language
The provided code is designed to visualize the generation of a Sierpinski pentagon, which is a fractal pattern that exhibits self-similarity. It primarily consists of the following:
-
Import Statements: The code begins by importing the necessary packages for creating graphical user interfaces and manipulating colors.
-
SierpinskiPentagon
Class:- This is the main class responsible for creating the fractal image and includes the following:
- Constants: Various constants are defined to control the scaling, angles, and margins of the pentagons.
- Constructor: The constructor initializes the panel's preferred size, background color, and sets up a timer to incrementally increase the depth of the fractal over time.
drawPentagon
Method: This method takes several parameters and draws a single pentagon. Here's how it works:- If the depth is 0 (the base case), it creates a
Path2D
and defines the vertices of the pentagon based on the provided coordinates, side length, and angle. It then fills the shape with a random hue. - If the depth is greater than 0, it calculates the scaled side length and the distance between the vertices of the pentagons in the next level.
- The method then recursively calls itself to draw the pentagons in the next level, moving around the virtual pentagon formed by their top vertices.
- If the depth is 0 (the base case), it creates a
paintComponent
Method: This method is called by the system to paint the component. It sets some rendering hints for anti-aliasing, calculates the radius and side length of the base pentagon, and calls thedrawPentagon
method to draw the initial pentagon with the specified depth.
-
main
Method:- This is the entry point of the program. It sets up the GUI using Swing and creates a JFrame with the
SierpinskiPentagon
as its content pane.
- This is the entry point of the program. It sets up the GUI using Swing and creates a JFrame with the
-
RandomHue
Class:- This class is used to generate random colors for the pentagons and employs a golden ratio conjugate algorithm to avoid clustering of similar colors.
Overall, the code demonstrates the creation of a Sierpinski pentagon fractal, which is an interesting example of how complex patterns can emerge from simple rules. When run, the program generates a dynamic fractal image where the depth of the fractal increases over time.
Source code in the java programming language
import java.awt.*;
import java.awt.event.ActionEvent;
import java.awt.geom.Path2D;
import static java.lang.Math.*;
import java.util.Random;
import javax.swing.*;
public class SierpinskiPentagon extends JPanel {
// exterior angle
final double degrees072 = toRadians(72);
/* After scaling we'll have 2 sides plus a gap occupying the length
of a side before scaling. The gap is the base of an isosceles triangle
with a base angle of 72 degrees. */
final double scaleFactor = 1 / (2 + cos(degrees072) * 2);
final int margin = 20;
int limit = 0;
Random r = new Random();
public SierpinskiPentagon() {
setPreferredSize(new Dimension(640, 640));
setBackground(Color.white);
new Timer(3000, (ActionEvent e) -> {
limit++;
if (limit >= 5)
limit = 0;
repaint();
}).start();
}
void drawPentagon(Graphics2D g, double x, double y, double side, int depth) {
double angle = 3 * degrees072; // starting angle
if (depth == 0) {
Path2D p = new Path2D.Double();
p.moveTo(x, y);
// draw from the top
for (int i = 0; i < 5; i++) {
x = x + cos(angle) * side;
y = y - sin(angle) * side;
p.lineTo(x, y);
angle += degrees072;
}
g.setColor(RandomHue.next());
g.fill(p);
} else {
side *= scaleFactor;
/* Starting at the top of the highest pentagon, calculate
the top vertices of the other pentagons by taking the
length of the scaled side plus the length of the gap. */
double distance = side + side * cos(degrees072) * 2;
/* The top positions form a virtual pentagon of their own,
so simply move from one to the other by changing direction. */
for (int i = 0; i < 5; i++) {
x = x + cos(angle) * distance;
y = y - sin(angle) * distance;
drawPentagon(g, x, y, side, depth - 1);
angle += degrees072;
}
}
}
@Override
public void paintComponent(Graphics gg) {
super.paintComponent(gg);
Graphics2D g = (Graphics2D) gg;
g.setRenderingHint(RenderingHints.KEY_ANTIALIASING,
RenderingHints.VALUE_ANTIALIAS_ON);
int w = getWidth();
double radius = w / 2 - 2 * margin;
double side = radius * sin(PI / 5) * 2;
drawPentagon(g, w / 2, 3 * margin, side, limit);
}
public static void main(String[] args) {
SwingUtilities.invokeLater(() -> {
JFrame f = new JFrame();
f.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
f.setTitle("Sierpinski Pentagon");
f.setResizable(true);
f.add(new SierpinskiPentagon(), BorderLayout.CENTER);
f.pack();
f.setLocationRelativeTo(null);
f.setVisible(true);
});
}
}
class RandomHue {
/* Try to avoid random color values clumping together */
final static double goldenRatioConjugate = (sqrt(5) - 1) / 2;
private static double hue = Math.random();
static Color next() {
hue = (hue + goldenRatioConjugate) % 1;
return Color.getHSBColor((float) hue, 1, 1);
}
}
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