How to resolve the algorithm Solve a Numbrix puzzle step by step in the AutoHotkey programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Solve a Numbrix puzzle step by step in the AutoHotkey programming language
Table of Contents
Problem Statement
Numbrix puzzles are similar to Hidato. The most important difference is that it is only possible to move 1 node left, right, up, or down (sometimes referred to as the Von Neumann neighborhood). Published puzzles also tend not to have holes in the grid and may not always indicate the end node. Two examples follow: Problem. Solution. Problem. Solution. Write a program to solve puzzles of this ilk, demonstrating your program by solving the above examples. Extra credit for other interesting examples.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Solve a Numbrix puzzle step by step in the AutoHotkey programming language
Source code in the autohotkey programming language
SolveNumbrix(Grid, Locked, Max, row, col, num:=1, R:="", C:=""){
if (R&&C) ; if neighbors (not first iteration)
{
Grid[R, C] := ">" num ; place num in current neighbor and mark it visited ">"
row:=R, col:=C ; move to current neighbor
}
num++ ; increment num
if (num=max) ; if reached end
return map(Grid) ; return solution
if locked[num] ; if current num is a locked value
{
row := StrSplit((StrSplit(locked[num], ",").1) , ":").1 ; find row of num
col := StrSplit((StrSplit(locked[num], ",").1) , ":").2 ; find col of num
if SolveNumbrix(Grid, Locked, Max, row, col, num) ; solve for current location and value
return map(Grid) ; if solved, return solution
}
else
{
for each, value in StrSplit(Neighbor(row,col), ",")
{
R := StrSplit(value, ":").1
C := StrSplit(value, ":").2
if (Grid[R,C] = "") ; a hole or out of bounds
|| InStr(Grid[R, C], ">") ; visited
|| Locked[num+1] && !(Locked[num+1]~= "\b" R ":" C "\b") ; not neighbor of locked[num+1]
|| Locked[num-1] && !(Locked[num-1]~= "\b" R ":" C "\b") ; not neighbor of locked[num-1]
|| Locked[num] ; locked value
|| Locked[Grid[R, C]] ; locked cell
continue
if SolveNumbrix(Grid, Locked, Max, row, col, num, R, C) ; solve for current location, neighbor and value
return map(Grid) ; if solved, return solution
}
}
num-- ; step back
for i, line in Grid
for j, element in line
if InStr(element, ">") && (StrReplace(element, ">") >= num)
Grid[i, j] := 0
}
;--------------------------------
;--------------------------------
;--------------------------------
Neighbor(row,col){
return row-1 ":" col
. "," row+1 ":" col
. "," row ":" col+1
. "," row ":" col-1
}
;--------------------------------
map(Grid){
for i, row in Grid
{
for j, element in row
line .= (A_Index > 1 ? "`t" : "") . element
map .= (map<>""?"`n":"") line
line := ""
}
return StrReplace(map, ">")
}
;--------------------------------
Grid := [[0, 0, 0, 0, 0, 0, 0, 0, 0]
,[0, 0, 46, 45, 0, 55, 74, 0, 0]
,[0, 38, 0, 0, 43, 0, 0, 78, 0]
,[0, 35, 0, 0, 0, 0, 0, 71, 0]
,[0, 0, 33, 0, 0, 0, 59, 0, 0]
,[0, 17, 0, 0, 0, 0, 0, 67, 0]
,[0, 18, 0, 0, 11, 0, 0, 64, 0]
,[0, 0, 24, 21, 0, 1, 2, 0, 0]
,[0, 0, 0, 0, 0, 0, 0, 0, 0]]
;--------------------------------
; find locked cells, find row and col of first value "1" and max value
Locked := []
max := 1
for i, line in Grid
for j, element in line
{
max ++
if element = 1
row :=i , col := j
if (element > 0)
Locked[element] := i ":" j "," Neighbor(i, j) ; save locked elements position and neighbors
}
;--------------------------------
MsgBox, 262144, ,% SolveNumbrix(Grid, Locked, Max, row, col)
return
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