Step by Step solution about How to resolve the algorithm Sort a list of object identifiers step by step in the Haskell programming language

The provided Haskell code defines several functions to sort a list of Object Identifiers (OIDs) in numerical order. Here's a breakdown of each function:

1. splitString :: Eq a => (a) -> [a] -> [[a]]:

• This function splits a string into a list of substrings based on a delimiter character c.
• It uses the break function to split the string into two parts: one part containing all characters up to and including the first occurrence of c, and another part containing the rest of the string.
• It then recursively calls itself on the remaining string, continuing to split it until no more delimiters are found.

2. convertIntListToString :: [Int] -> String:

• This function converts a list of integers into a string by converting each integer to a string and joining the strings with "." as a separator.

**3. orderOID :: [String] -> [String]:

• This function is the main function for sorting OIDs.
• It first splits each OID string (which represents a dotted decimal notation of an OID) into a list of strings, each representing a component of the OID.
• It then converts each component to an integer using the read function and then uses the sort function to sort the list of integer lists.
• Finally, it uses the convertIntListToString function to convert each sorted list of integers back into a dotted-decimal string.

**4. oidSort :: [String] -> [String]: (from the second code snippet)

• This function is similar to orderOID but uses a different approach.
• It first splits each OID string into a list of strings, as in orderOID.
• Then, it uses the fmap function to apply the fmap readInt function to each string. This function converts each string to an integer.
• It then sorts the resulting list of integer lists using the sort function.
• Finally, it uses the fmap function to apply the intercalate "." function to each sorted list of integers, which joins the integers with "." as a separator.

5. oid: This is a sample list of OID strings used for testing.

6. main: This function is the entry point of the program.

• It uses the mapM_ putStrLn function to print the sorted OID strings to the standard output.

The code uses the Data.List module for list manipulation, the Data.List.Split module for string splitting, and the Data.Text module for text manipulation.

import Data.List ( sort , intercalate ) 

splitString :: Eq a => (a) -> [a] -> [[a]]
splitString c [] = []
splitString c s = let ( item , rest ) = break ( == c ) s
                      ( _ , next ) = break ( /= c ) rest
		  in item : splitString c next

convertIntListToString :: [Int] -> String
convertIntListToString = intercalate "." . map show

orderOID :: [String] -> [String]
orderOID = map convertIntListToString . sort . map ( map read . splitString '.' )

oid :: [String]
oid = ["1.3.6.1.4.1.11.2.17.19.3.4.0.10" ,
    "1.3.6.1.4.1.11.2.17.5.2.0.79" ,
    "1.3.6.1.4.1.11.2.17.19.3.4.0.4" ,
    "1.3.6.1.4.1.11150.3.4.0.1" ,
    "1.3.6.1.4.1.11.2.17.19.3.4.0.1" ,
    "1.3.6.1.4.1.11150.3.4.0"]

main :: IO ( )
main = do
   mapM_ putStrLn $ orderOID oid


import Data.Text (pack, split, unpack)
import Data.List (sort, intercalate)

-- SORTING OBJECT IDENTIFIERS ------------------------------------------------
oidSort :: [String] -> [String]
oidSort =
  fmap (intercalate "." . fmap show) .
  sort . fmap (fmap readInt . splitString '.')

-- GENERIC FUNCTIONS ---------------------------------------------------------
splitString :: Char -> String -> [String]
splitString c s = unpack <$> split (c ==) (pack s)

readInt :: String -> Int
readInt xs = read xs :: Int

-- TEST ----------------------------------------------------------------------
main :: IO ()
main =
  mapM_ putStrLn $
  oidSort
    [ "1.3.6.1.4.1.11.2.17.19.3.4.0.10"
    , "1.3.6.1.4.1.11.2.17.5.2.0.79"
    , "1.3.6.1.4.1.11.2.17.19.3.4.0.4"
    , "1.3.6.1.4.1.11150.3.4.0.1"
    , "1.3.6.1.4.1.11.2.17.19.3.4.0.1"
    , "1.3.6.1.4.1.11150.3.4.0"
    ]


import Data.List.Split (splitOn)
import Data.List (sort, intercalate)

-- SORTING OBJECT IDENTIFIERS ------------------------------------------------
oidSort :: [String] -> [String]
oidSort =
  fmap (intercalate "." . fmap show) . sort . fmap (fmap readInt . splitOn ".")

readInt :: String -> Int
readInt x = read x :: Int