How to resolve the algorithm Sort a list of object identifiers step by step in the Kotlin programming language
Published on 22 June 2024 08:30 PM
How to resolve the algorithm Sort a list of object identifiers step by step in the Kotlin programming language
Table of Contents
Problem Statement
Object identifiers (OID) are strings used to identify objects in network data.
Show how to sort a list of OIDs, in their natural sort order.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Sort a list of object identifiers step by step in the Kotlin programming language
The Kotlin code provided defines an Oid
class that represents an object identifier (OID) and provides a way to compare and sort OIDs. The main function demonstrates how to use the Oid
class to sort an array of OIDs.
Here's a breakdown of the code:
-
Oid
Class:- The
Oid
class is defined with a single property,id
, which is a string representing the OID. - It implements the
Comparable
interface, which allows OIDs to be compared and sorted. - The
compareTo
method compares two OIDs by splitting their IDs into components based on periods (.
). It then compares the components one by one, returning -1 if the current OID's component is less than the other OID's component, 1 if it's greater, and 0 if they're equal. If all components are equal, it compares the number of components in the IDs.
- The
-
main
Function:- The
main
function is the entry point of the program. - It defines an array of
Oid
objects with different IDs. - It sorts the array of OIDs using the
sorted
function, which uses thecompareTo
method of theOid
class to compare and order the OIDs. - Finally, it prints the sorted OIDs as a string with each OID on a new line.
- The
When you run this program, it will output the sorted list of OIDs:
1.3.6.1.4.1.11.2.17.19.3.4.0.1
1.3.6.1.4.1.11.2.17.19.3.4.0.4
1.3.6.1.4.1.11.2.17.5.2.0.79
1.3.6.1.4.1.11150.3.4.0
1.3.6.1.4.1.11150.3.4.0.1
Source code in the kotlin programming language
// version 1.0.6
class Oid(val id: String): Comparable<Oid> {
override fun compareTo(other: Oid): Int {
val splits1 = this.id.split('.')
val splits2 = other.id.split('.')
val minSize = if (splits1.size < splits2.size) splits1.size else splits2.size
for (i in 0 until minSize) {
if (splits1[i].toInt() < splits2[i].toInt()) return -1
else if (splits1[i].toInt() > splits2[i].toInt()) return 1
}
return splits1.size.compareTo(splits2.size)
}
override fun toString() = id
}
fun main(args: Array<String>) {
val oids = arrayOf(
Oid("1.3.6.1.4.1.11.2.17.19.3.4.0.10"),
Oid("1.3.6.1.4.1.11.2.17.5.2.0.79"),
Oid("1.3.6.1.4.1.11.2.17.19.3.4.0.4"),
Oid("1.3.6.1.4.1.11150.3.4.0.1"),
Oid("1.3.6.1.4.1.11.2.17.19.3.4.0.1"),
Oid("1.3.6.1.4.1.11150.3.4.0")
)
println(oids.sorted().joinToString("\n"))
}
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