Step by Step solution about How to resolve the algorithm Sort an integer array step by step in the Ruby programming language

The provided Ruby code demonstrates the difference between the sort and sort! methods for sorting arrays.

• The sort method creates and returns a new sorted array, leaving the original array unchanged.
• The sort! method modifies the original array in-place, sorting its elements.

The code starts with an array nums containing the unsorted numbers [2, 4, 3, 1, 2].

• The first sort call creates a new sorted array named sorted by rearranging the elements of nums in ascending order. nums remains unchanged. The output of p sorted shows the sorted array: [1, 2, 2, 3, 4]. The output of p nums shows that nums is still the original unsorted array: [2, 4, 3, 1, 2].

• The second sort! call modifies nums in-place, sorting its elements. After this call, nums itself becomes sorted. The output of p nums shows the sorted nums array: [1, 2, 2, 3, 4].

In summary, sort creates a new sorted array without altering the original array, while sort! modifies the original array by sorting its elements in ascending order.

nums = [2,4,3,1,2]
sorted = nums.sort      # returns a new sorted array.  'nums' is unchanged
p sorted                #=> [1, 2, 2, 3, 4]
p nums                  #=> [2, 4, 3, 1, 2]

nums.sort!              # sort 'nums' "in-place"
p nums                  #=> [1, 2, 2, 3, 4]