How to resolve the algorithm Sort numbers lexicographically step by step in the C# programming language
How to resolve the algorithm Sort numbers lexicographically step by step in the C# programming language
Table of Contents
Problem Statement
Given an integer n, return 1──►n (inclusive) in lexicographical order.
Show all output here on this page.
Given 13, return: [1,10,11,12,13,2,3,4,5,6,7,8,9].
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Sort numbers lexicographically step by step in the C# programming language
This C# code defines a program that takes an integer n
and prints out the lexicographic order of the numbers from 1 to n
(if n
is positive) or from n
to 1 (if n
is negative), separated by commas.
Here's how the code works step by step:
-
The
Main
method takes an integern
as input and prints out the lexicographic order of the numbers from 1 ton
(ifn
is positive) or fromn
to 1 (ifn
is negative). -
The
LexOrder
method takes an integern
as input and returns anIEnumerable
of integers representing the lexicographic order of the numbers from 1 ton
(ifn
is positive) or fromn
to 1 (ifn
is negative). -
The
Range
method is used to generate a sequence of integers fromn
to 2 -n
. TheOrderBy
method is then used to sort the sequence of integers in lexicographic order. -
The
ToString
method is used to convert each integer in the sequence to a string. TheJoin
method is then used to concatenate the strings into a single string, with commas separating the individual strings. -
Finally, the resulting string is printed out to the console.
Source code in the csharp programming language
using static System.Console;
using static System.Linq.Enumerable;
public class Program
{
public static void Main() {
foreach (int n in new [] { 0, 5, 13, 21, -22 }) WriteLine($"{n}: {string.Join(", ", LexOrder(n))}");
}
public static IEnumerable<int> LexOrder(int n) => (n < 1 ? Range(n, 2 - n) : Range(1, n)).OrderBy(i => i.ToString());
}
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