How to resolve the algorithm Sort numbers lexicographically step by step in the C# programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Sort numbers lexicographically step by step in the C# programming language

Table of Contents

Problem Statement

Given an integer   n,   return   1──►n   (inclusive)   in lexicographical order.

Show all output here on this page.

Given   13, return:   [1,10,11,12,13,2,3,4,5,6,7,8,9].

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Sort numbers lexicographically step by step in the C# programming language

This C# code defines a program that takes an integer n and prints out the lexicographic order of the numbers from 1 to n (if n is positive) or from n to 1 (if n is negative), separated by commas.

Here's how the code works step by step:

  1. The Main method takes an integer n as input and prints out the lexicographic order of the numbers from 1 to n (if n is positive) or from n to 1 (if n is negative).

  2. The LexOrder method takes an integer n as input and returns an IEnumerable of integers representing the lexicographic order of the numbers from 1 to n (if n is positive) or from n to 1 (if n is negative).

  3. The Range method is used to generate a sequence of integers from n to 2 - n. The OrderBy method is then used to sort the sequence of integers in lexicographic order.

  4. The ToString method is used to convert each integer in the sequence to a string. The Join method is then used to concatenate the strings into a single string, with commas separating the individual strings.

  5. Finally, the resulting string is printed out to the console.

Source code in the csharp programming language

using static System.Console;
using static System.Linq.Enumerable;

public class Program
{
    public static void Main() {
        foreach (int n in new [] { 0, 5, 13, 21, -22 }) WriteLine($"{n}: {string.Join(", ", LexOrder(n))}");
    }

    public static IEnumerable<int> LexOrder(int n) => (n < 1 ? Range(n, 2 - n) : Range(1, n)).OrderBy(i => i.ToString());
}


  

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