How to resolve the algorithm Sorting algorithms/Patience sort step by step in the JavaScript programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Sorting algorithms/Patience sort step by step in the JavaScript programming language

Table of Contents

Problem Statement

Sort an array of numbers (of any convenient size) into ascending order using   Patience sorting.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Sorting algorithms/Patience sort step by step in the JavaScript programming language

This JavaScript code implements the Patience Sorting algorithm, also known as the Build-a-Pile algorithm, to sort an array of numbers in ascending order. It follows these steps:

  1. Initialize empty piles (an array of arrays).

  2. Iterate through the input array and for each element:

    • Find the destination pile where the element can be placed, ensuring that it is greater than or equal to the previous element in the pile.
    • If no suitable pile is found, create a new pile with the element.
  3. After placing all elements in the piles, merge the piles back into the input array in sorted order.

    • Find the pile with the smallest top element.
    • Move the top element of that pile to the output array.
    • If the pile is now empty, remove it.
  4. Repeat step 3 until all piles are merged.

The provided example sorts the array [10,6,-30,9,18,1,-20] using the Patience Sort algorithm. The result is [-30,-20,1,6,9,10,18], which is the sorted version of the input array.

The provided JavaScript code implements a Patience Sort algorithm, which arranges a given array of integers (nums) into sorted order in a specific manner. Here's a detailed explanation of the code:

  1. Initialization:

    • An empty array called piles is created to store piles (lists) of integers. Each pile represents a sorted sequence of numbers.
  2. Populating Piles:

    • The code iterates through each number (num) in the nums array using a for loop.
    • For each number:
      • It finds the destination pile index (destinationPileIndex) where num can be placed in ascending order using the findIndex method.
      • If a suitable pile is found for num, it is pushed onto that pile.
      • Otherwise, a new pile is created containing just num.
  3. Extracting Sorted Elements:

    • After populating the piles, a second for loop iterates through the indices of the original nums array.
    • In each iteration, it finds the pile with the smallest top element (destinationPileIndex) among all the piles.
    • The top element of the destination pile is removed (shift()) and assigned to the corresponding index in the nums array.
    • If the destination pile becomes empty after the removal, it is removed from the piles array using splice().
  4. Final Result:

    • This process continues until all numbers have been placed in the nums array in sorted order.
    • Finally, the sorted nums array is returned as the result.
  5. Example Usage:

    • At the end of the code, an example array, [10, 6, -30, 9, 18, 1, -20], is passed to the patienceSort function, and the sorted result is printed to the console.

In summary, Patience Sort operates by building piles of sorted numbers, where each pile represents a descending sequence. The algorithm then iteratively extracts the smallest top element from the piles, placing them in the correct order in the original array. This results in a sorted array while maintaining the relative order of numbers within each pile.

Source code in the javascript programming language

const patienceSort = (nums) => {
  const piles = []

  for (let i = 0; i < nums.length; i++) {
    const num = nums[i]
    const destinationPileIndex = piles.findIndex(
      (pile) => num >= pile[pile.length - 1]
    )
    if (destinationPileIndex === -1) {
      piles.push([num])
    } else {
      piles[destinationPileIndex].push(num)
    }
  }

  for (let i = 0; i < nums.length; i++) {
    let destinationPileIndex = 0
    for (let p = 1; p < piles.length; p++) {
      const pile = piles[p]
      if (pile[0] < piles[destinationPileIndex][0]) {
        destinationPileIndex = p
      }
    }
    const distPile = piles[destinationPileIndex]
    nums[i] = distPile.shift()
    if (distPile.length === 0) {
      piles.splice(destinationPileIndex, 1)
    }
  }

  return nums
}
console.log(patienceSort([10,6,-30,9,18,1,-20]));


  

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