How to resolve the algorithm Sorting algorithms/Shell sort step by step in the Yabasic programming language
How to resolve the algorithm Sorting algorithms/Shell sort step by step in the Yabasic programming language
Table of Contents
Problem Statement
Sort an array of elements using the Shell sort algorithm, a diminishing increment sort. The Shell sort (also known as Shellsort or Shell's method) is named after its inventor, Donald Shell, who published the algorithm in 1959. Shell sort is a sequence of interleaved insertion sorts based on an increment sequence. The increment size is reduced after each pass until the increment size is 1. With an increment size of 1, the sort is a basic insertion sort, but by this time the data is guaranteed to be almost sorted, which is insertion sort's "best case". Any sequence will sort the data as long as it ends in 1, but some work better than others. Empirical studies have shown a geometric increment sequence with a ratio of about 2.2 work well in practice. [1] Other good sequences are found at the On-Line Encyclopedia of Integer Sequences.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Sorting algorithms/Shell sort step by step in the Yabasic programming language
Source code in the yabasic programming language
export sub shell_sort(x())
// Shell sort based on insertion sort
local gap, i, j, first, last, tempi, tempj
last = arraysize(x(),1)
gap = int(last / 10) + 1
while(TRUE)
first = gap + 1
for i = first to last
tempi = x(i)
j = i - gap
while(TRUE)
tempj = x(j)
if tempi >= tempj then
j = j + gap
break
end if
x(j+gap) = tempj
if j <= gap then
break
end if
j = j - gap
wend
x(j) = tempi
next i
if gap = 1 then
return
else
gap = int(gap / 3.5) + 1
end if
wend
end sub
if peek$("library") = "main" then
clear screen
ITEMS = 100
dim numeros(ITEMS)
for n = 1 to ITEMS
numeros(n) = ran(ITEMS + 1)
next n
print time$
shell_sort(numeros())
print time$
print "Press a key to see ordered numbers."
inkey$
for n = 1 to ITEMS
print numeros(n),", ";
next n
end if
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