Step by Step solution about How to resolve the algorithm Spelling of ordinal numbers step by step in the Julia programming language

Code Overview:

This code converts number text or string representations of numbers into ordinal numbers, which are used to indicate the position or order of items in a sequence. It handles special cases for irregular ordinals and applies appropriate suffixes to regular ordinals.

Implementation Details:

1. Regular and Irregular Ordinals:

const irregular is a dictionary that maps irregular ordinal numbers (e.g., "one" -> "first") to their standard equivalents.

2. Suffixes:

const suffix represents the standard "th" suffix for regular ordinals. const ysuffix represents the "ieth" suffix for numbers ending in "y" (e.g., "twenty-nine" -> "twenty-ninth").

3. numtext2ordinal Function:

• Split Last Word:

  • Splits the input string into words.
  • Stores the last word and checks if it has a "-" indicating multiple words or just a single word.

• Separate First Part:

  • If the last word has a "-" indicating multiple words, split it at the "-" and remove the last part.
  • If the last word has no "-", use the entire input string.

• Irregular/Regular Ordinal Conversion:

  • If the last word is an irregular ordinal, replace it with its standard equivalent from irregular.
  • If the last word ends in "y", replace it with the "ieth" suffix.
  • Otherwise, append the standard "th" suffix.

• Assemble Ordinal:

  • Combine the first part (e.g., "twenty") with the ordinalized last word.

4. Test Cases:

The code includes a list of test cases in testcases. It iterates through these test cases and converts the numbers (represented as strings) to ordinal numbers.

5. Output:

For each test case, the code prints the original number and its ordinal representation.

const irregular = Dict("one" => "first", "two" => "second", "three" => "third", "five" => "fifth", 
                                "eight" => "eighth", "nine" => "ninth", "twelve" => "twelfth")
const suffix = "th"
const ysuffix = "ieth"

function numtext2ordinal(s)
    lastword = split(s)[end]
    redolast = split(lastword, "-")[end]
    if redolast != lastword
        lastsplit = "-"
        word = redolast
    else
        lastsplit = " "
        word = lastword
    end
    firstpart = reverse(split(reverse(s), lastsplit, limit=2)[end])
    firstpart = (firstpart == word) ? "": firstpart * lastsplit
    if haskey(irregular, word)
        word = irregular[word]
    elseif word[end] == 'y'
        word = word[1:end-1] * ysuffix
    else
        word = word * suffix
    end
    firstpart * word
end

const testcases =  [1  2  3  4  5  11  65  100  101  272  23456  8007006005004003]
for n in testcases
    println("$n => $(numtext2ordinal(num2text(n)))")
end