How to resolve the algorithm Spinning rod animation/Text step by step in the Java programming language
How to resolve the algorithm Spinning rod animation/Text step by step in the Java programming language
Table of Contents
Problem Statement
An animation with the following frames in the following order (if certain characters aren't available or can't be used correctly in the programming language, alternate characters can replace any of these frames) must animate with a delay of 0.25 seconds between each frame, with the previous frame being cleared before the next frame appears:
A stand-alone version that loops and/or a version that doesn't loop can be made. These examples can also be converted into a system used in game development which is called on a HUD or GUI element requiring it to be called each frame to output the text, and advance the frame when the frame delay has passed. You can also use alternate text such as the . animation ( . | .. | ... | .. | repeat from . ) or the logic can be updated to include a ping/pong style where the frames advance forward, reach the end and then play backwards and when they reach the beginning they start over ( technically, you'd stop one frame prior to prevent the first frame playing twice, or write it another way ).
There are many different ways you can incorporate text animations. Here are a few text ideas - each frame is in quotes. If you can think of any, add them to this page! There are 2 examples for several of these; the first is the base animation with only unique sets of characters. The second consists of the primary set from a - n and doubled, minus the first and last element ie: We only want the center. This way an animation can play forwards, and then in reverse ( ping ponging ) without having to code that feature. For the animations with 3 elements, we only add 1, the center. with 4, it becomes 6. with 10, it becomes 18.
We don't need the second option for some of the animations if they connect smoothly, when animated, back to the first element. ... doesn't connect with . cleanly - there is a large leap. The rotating pipe meets the first perfectly so it isn't necessary, etc..
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Spinning rod animation/Text step by step in the Java programming language
The Java code you provided is a simple program that prints a spinning rod on the terminal. The program uses the System.out.print()
method to print the rod and the Thread.sleep()
method to pause the program for a short period of time. The \033[2J
escape sequence is used to clear the terminal and the \033[0;0H
escape sequence is used to place the cursor at the top left corner of the terminal. The \033[?25h
escape sequence is used to restore the cursor.
Here is a breakdown of the code:
- The
main()
method is the entry point of the program. It initializes the stringa
to the value "|/-\". This string represents the four different positions of the spinning rod. - The
System.out.print("\033[2J");
line clears the terminal. - The
long start = System.currentTimeMillis();
line gets the current time in milliseconds. This time is used to track how long the program has been running. - The
while (true)
loop is the main loop of the program. It will continue to run until thebreak
statement is executed. - The
for (int i = 0; i < 4; i++)
loop iterates through the four different positions of the spinning rod. - The
System.out.print("\033[2J");
line clears the terminal. - The
System.out.print("\033[0;0H");
line places the cursor at the top left corner of the terminal. - The
for (int j = 0; j < 80; j++)
loop prints the spinning rod. The number80
represents the width of the terminal in characters. - The
Thread.sleep(250);
line pauses the program for 250 milliseconds. This gives the user time to see the spinning rod. - The
long now = System.currentTimeMillis();
line gets the current time in milliseconds. - The
if (now - start >= 20000) break;
line checks if the program has been running for more than 20 seconds. If so, thebreak
statement is executed and the program exits. - The
System.out.print("\033[?25h");
line restores the cursor.
The output of the program is a spinning rod that rotates on the terminal. The rod will continue to spin until the program has been running for 20 seconds.
Source code in the java programming language
public class SpinningRod
{
public static void main(String[] args) throws InterruptedException {
String a = "|/-\\";
System.out.print("\033[2J"); // hide the cursor
long start = System.currentTimeMillis();
while (true) {
for (int i = 0; i < 4; i++) {
System.out.print("\033[2J"); // clear terminal
System.out.print("\033[0;0H"); // place cursor at top left corner
for (int j = 0; j < 80; j++) { // 80 character terminal width, say
System.out.print(a.charAt(i));
}
Thread.sleep(250);
}
long now = System.currentTimeMillis();
// stop after 20 seconds, say
if (now - start >= 20000) break;
}
System.out.print("\033[?25h"); // restore the cursor
}
}
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