How to resolve the algorithm Split a character string based on change of character step by step in the Ruby programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Split a character string based on change of character step by step in the Ruby programming language

Table of Contents

Problem Statement

Split a (character) string into comma (plus a blank) delimited strings based on a change of character   (left to right). Show the output here   (use the 1st example below).

Blanks should be treated as any other character   (except they are problematic to display clearly).   The same applies to commas.

For instance, the string: should be split and show:

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Split a character string based on change of character step by step in the Ruby programming language

The provided Ruby code defines a method called split that takes a string as input and performs a specific transformation on it. Here's a detailed explanation of the code:

  1. def split(str): This line defines a method named split that accepts one parameter, str. This parameter is expected to be a string.

  2. puts " input string: #{str}": This line prints the input string to the console. It's a helpful debugging statement that shows the original string before the transformation.

  3. s = str.chars.chunk(&:itself).map{|_,a| a.join}.join(", "): This line performs the main transformation on the input string. Let's break it down:

    • str.chars: This converts the input string into an array of individual characters.
    • chunk(&:itself): This method groups consecutive identical characters in the array. It returns an array of subarrays, where each subarray contains characters that are the same.
    • map{|_,a| a.join}: This iterates over the subarrays and joins the characters in each subarray back into a single string. The underscore (_) is a placeholder variable that is not used.
    • join(", "): This joins the strings from the previous step with a comma and space as a separator.
  4. puts "output string: #{s}": This line prints the transformed string to the console. It shows the result after performing the specified transformation.

  5. s: This is the return value of the split method. It contains the transformed string.

  6. split("gHHH5YY++///\\"): This line calls the split method with the string "gHHH5YY++///\" as input. The transformed string is then printed to the console.

When you run this code, it will print the input and output strings as follows:

input string: gHHH5YY++///\\
output string: g, HHH, 5, YY, ++, ///, \\

In this example, the input string is first split into its individual characters:

['g', 'H', 'H', 'H', '5', 'Y', 'Y', '+', '+', '/', '/', '/', '\\']

Then, consecutive identical characters are grouped together:

[['g', 'g'], ['H', 'H', 'H'], ['5'], ['Y', 'Y'], ['+', '+'], ['/', '/', '/'], ['\\']]

Finally, the characters in each group are joined back into a single string, separated by commas and spaces. The resulting output string is "g, HHH, 5, YY, ++, ///, \".

Source code in the ruby programming language

def split(str)
  puts " input string: #{str}"
  s = str.chars.chunk(&:itself).map{|_,a| a.join}.join(", ")
  puts "output string: #{s}"
  s
end

split("gHHH5YY++///\\")


  

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