How to resolve the algorithm Stack step by step in the EchoLisp programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Stack step by step in the EchoLisp programming language

Table of Contents

Problem Statement

A stack is a container of elements with   last in, first out   access policy.   Sometimes it also called LIFO. The stack is accessed through its top. The basic stack operations are:

Sometimes the last pushed stack element is made accessible for immutable access (for read) or mutable access (for write):

Stacks allow a very simple hardware implementation. They are common in almost all processors. In programming, stacks are also very popular for their way (LIFO) of resource management, usually memory. Nested scopes of language objects are naturally implemented by a stack (sometimes by multiple stacks). This is a classical way to implement local variables of a re-entrant or recursive subprogram. Stacks are also used to describe a formal computational framework. See stack machine. Many algorithms in pattern matching, compiler construction (e.g. recursive descent parsers), and machine learning (e.g. based on tree traversal) have a natural representation in terms of stacks.

Create a stack supporting the basic operations: push, pop, empty.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Stack step by step in the EchoLisp programming language

Source code in the echolisp programming language

; build stack [0 1 ... 9 (top)] from a list
(list->stack (iota 10) 'my-stack)
(stack-top 'my-stack) → 9
(pop 'my-stack)  → 9
(stack-top 'my-stack) → 8
(push 'my-stack '🐸) ; any kind of lisp object in the stack
(stack-empty? 'my-stack) → #f
(stack->list 'my-stack) ; convert stack to list
    → (0 1 2 3 4 5 6 7 8 🐸)
(stack-swap 'my-stack) ; swaps two last items 
    → 8 ; new top
(stack->list 'my-stack)
     → (0 1 2 3 4 5 6 7 🐸 8) ; swapped
(while (not (stack-empty? 'my-stack)) (pop 'my-stack)) ; pop until empty
(stack-empty? 'my-stack)  → #t ; true

(push 'my-stack 7)
my-stack ; a stack is not a variable, nor a symbol - cannot be evaluated
   ⛔ error: #|user| : unbound variable : my-stack
(stack-top 'my-stack)  → 7


  

You may also check:How to resolve the algorithm Count in octal step by step in the FutureBasic programming language
You may also check:How to resolve the algorithm Call a function step by step in the Ecstasy programming language
You may also check:How to resolve the algorithm Averages/Root mean square step by step in the Phixmonti programming language
You may also check:How to resolve the algorithm Letter frequency step by step in the FBSL programming language
You may also check:How to resolve the algorithm Sorting algorithms/Insertion sort step by step in the ML programming language