How to resolve the algorithm Stack step by step in the X86 Assembly programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Stack step by step in the X86 Assembly programming language

Table of Contents

Problem Statement

A stack is a container of elements with   last in, first out   access policy.   Sometimes it also called LIFO. The stack is accessed through its top. The basic stack operations are:

Sometimes the last pushed stack element is made accessible for immutable access (for read) or mutable access (for write):

Stacks allow a very simple hardware implementation. They are common in almost all processors. In programming, stacks are also very popular for their way (LIFO) of resource management, usually memory. Nested scopes of language objects are naturally implemented by a stack (sometimes by multiple stacks). This is a classical way to implement local variables of a re-entrant or recursive subprogram. Stacks are also used to describe a formal computational framework. See stack machine. Many algorithms in pattern matching, compiler construction (e.g. recursive descent parsers), and machine learning (e.g. based on tree traversal) have a natural representation in terms of stacks.

Create a stack supporting the basic operations: push, pop, empty.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Stack step by step in the X86 Assembly programming language

Source code in the x86 programming language

; x86_64 linux nasm

struc Stack
  maxSize: resb 8
  currentSize: resb 8
  contents:
endStruc

section .data

soError: db "Stack Overflow Exception", 10
seError: db "Stack Empty Error", 10


section .text

createStack:
; IN: max number of elements (rdi)
; OUT: pointer to new stack (rax)
  push rdi
  xor rdx, rdx
  mov rbx, 8
  mul rbx
  mov rcx, rax
  mov rax, 12
  mov rdi, 0
  syscall
  push rax
  mov rdi, rax
  add rdi, rcx
  mov rax, 12
  syscall
  pop rax
  pop rbx
  mov qword [rax + maxSize], rbx
  mov qword [rax + currentSize], 0
  ret


push:
; IN: stack to operate on (stack argument), element to push (rdi)
; OUT: void
  mov rax, qword [rsp + 8]
  mov rbx, qword [rax + currentSize]
  cmp rbx, qword [rax + maxSize]
  je stackOverflow
  lea rsi, [rax + contents + 8*rbx]
  mov qword [rsi], rdi
  add qword [rax + currentSize], 1
  ret


pop:
; pop
; IN: stack to operate on (stack argument)
; OUT: element from stack top
  mov rax, qword [rsp + 8]
  mov rbx, qword [rax + currentSize]
  cmp rbx, 0
  je stackEmpty
  sub rbx, 1
  lea rsi, [rax + contents + 8*rbx]
  mov qword [rax + currentSize], rbx
  mov rax, qword [rsi]
  ret


; stack operation exceptions
stackOverflow:
  mov rsi, soError
  mov rdx, 25
  jmp errExit
stackEmpty:
  mov rsi, seError
  mov rdx, 18
errExit:
  mov rax, 1
  mov rdi, 1
  syscall
  mov rax, 60
  mov rdi, 1
  syscall

  

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