How to resolve the algorithm String prepend step by step in the C++ programming language
How to resolve the algorithm String prepend step by step in the C++ programming language
Table of Contents
Problem Statement
Create a string variable equal to any text value. Prepend the string variable with another string literal. If your language supports any idiomatic ways to do this without referring to the variable twice in one expression, include such solutions.
To illustrate the operation, show the content of the variable.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm String prepend step by step in the C++ programming language
The code snippet you provided is a C++ program that demonstrates the use of the std::accumulate
function to concatenate a vector of strings. Here's a detailed explanation of the code:
-
#include <vector>
: This line includes the C++ Standard Library header file that provides thestd::vector
class, which is used to represent a dynamically-sized array of elements. -
#include <algorithm>
: This line includes the C++ Standard Library header file that provides thestd::accumulate
function, which is used to reduce a sequence of values into a single value. -
#include <string>
: This line includes the C++ Standard Library header file that provides thestd::string
class, which is used to represent a string of characters. -
#include <iostream>
: This line includes the C++ Standard Library header file that provides thestd::cout
object, which is used to write data to the standard output stream (usually the console). -
int main()
: This is the entry point of the program. It defines themain
function, which is called when the program starts. -
std::vector<std::string> myStrings { "prepended to" , "my string" }
: This line declares astd::vector
namedmyStrings
and initializes it with two strings: "prepended to" and "my string". -
std::string prepended = std::accumulate( myStrings.begin( ), myStrings.end( ), std::string( "" ) , []( std::string a , std::string b ) { return a + b ; } )
: This line uses thestd::accumulate
function to concatenate the strings in themyStrings
vector. Here's how this line works:-
myStrings.begin()
: This returns an iterator pointing to the first element of themyStrings
vector. -
myStrings.end()
: This returns an iterator pointing to the element beyond the last element of themyStrings
vector. -
std::string( "" )
: This creates an empty string object, which serves as the initial value for the accumulation. -
[]( std::string a , std::string b ) { return a + b ; }
: This is a lambda function that takes twostd::string
arguments and returns the concatenation of those strings. -
The
std::accumulate
function calls the lambda function for each pair of adjacent elements in themyStrings
vector and accumulates the results into theprepended
string variable.
-
-
std::cout << prepended << std::endl ;
: This line uses thestd::cout
object to print theprepended
string to the standard output stream, followed by a newline character (std::endl
). -
return 0 ;
: This line indicates the end of themain
function and the end of the program. It returns 0 to the operating system, indicating that the program executed successfully.
Source code in the cpp programming language
include <vector>
#include <algorithm>
#include <string>
#include <iostream>
int main( ) {
std::vector<std::string> myStrings { "prepended to" , "my string" } ;
std::string prepended = std::accumulate( myStrings.begin( ) ,
myStrings.end( ) , std::string( "" ) , []( std::string a ,
std::string b ) { return a + b ; } ) ;
std::cout << prepended << std::endl ;
return 0 ;
}
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