How to resolve the algorithm Strip control codes and extended characters from a string step by step in the Icon and Unicon programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Strip control codes and extended characters from a string step by step in the Icon and Unicon programming language
Table of Contents
Problem Statement
Strip control codes and extended characters from a string.
The solution should demonstrate how to achieve each of the following results:
In ASCII, the control codes have decimal codes 0 through to 31 and 127. On an ASCII based system, if the control codes are stripped, the resultant string would have all of its characters within the range of 32 to 126 decimal on the ASCII table. On a non-ASCII based system, we consider characters that do not have a corresponding glyph on the ASCII table (within the ASCII range of 32 to 126 decimal) to be an extended character for the purpose of this task.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Strip control codes and extended characters from a string step by step in the Icon and Unicon programming language
Source code in the icon programming language
procedure main(A)
write(image(deletec(&ascii,&ascii--(&ascii)[33:127])))
end
link strings
procedure deletec(s, c) #: delete characters
result := ""
s ? {
while result ||:= tab(upto(c)) do tab(many(c))
return result ||:= tab(0)
}
end
You may also check:How to resolve the algorithm Variables step by step in the Rascal programming language
You may also check:How to resolve the algorithm Hello world/Line printer step by step in the OpenEdge/Progress programming language
You may also check:How to resolve the algorithm Palindrome detection step by step in the Modula-2 programming language
You may also check:How to resolve the algorithm Singleton step by step in the Vala programming language
You may also check:How to resolve the algorithm Bifid cipher step by step in the J programming language