How to resolve the algorithm Successive prime differences step by step in the Visual Basic .NET programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Successive prime differences step by step in the Visual Basic .NET programming language

Table of Contents

Problem Statement

The series of increasing prime numbers begins: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, ... The task applies a filter to the series returning groups of successive primes, (s'primes), that differ from the next by a given value or values. Example 1: Specifying that the difference between s'primes be 2 leads to the groups: (Known as Twin primes or Prime pairs) Example 2: Specifying more than one difference between s'primes leads to groups of size one greater than the number of differences. Differences of 2, 4 leads to the groups: In the first group 7 is two more than 5 and 11 is four more than 7; as well as 5, 7, and 11 being successive primes. Differences are checked in the order of the values given, (differences of 4, 2 would give different groups entirely). Note: Generation of a list of primes is a secondary aspect of the task. Use of a built in function, well known library, or importing/use of prime generators from other Rosetta Code tasks is encouraged.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Successive prime differences step by step in the Visual Basic .NET programming language

Source code in the visual programming language

Imports System.Text

Module Module1

    Function Sieve(limit As Integer) As Integer()
        Dim primes As New List(Of Integer) From {2}
        Dim c(limit + 1) As Boolean REM composite = true
        REM no need to process even numbers > 2
        Dim p = 3
        While True
            Dim p2 = p * p
            If p2 > limit Then
                Exit While
            End If
            For i = p2 To limit Step 2 * p
                c(i) = True
            Next
            Do
                p += 2
            Loop While c(p)
        End While
        For i = 3 To limit Step 2
            If Not c(i) Then
                primes.Add(i)
            End If
        Next
        Return primes.ToArray
    End Function

    Function SuccessivePrimes(primes() As Integer, diffs() As Integer) As List(Of List(Of Integer))
        Dim results As New List(Of List(Of Integer))
        Dim dl = diffs.Length
        Dim i = 0
        While i < primes.Length - dl
            Dim group(dl) As Integer
            group(0) = primes(i)

            Dim j = i
            While j < i + dl
                If primes(j + 1) - primes(j) <> diffs(j - i) Then
                    GoTo outer REM continue the outermost loop
                End If
                group(j - i + 1) = primes(j + 1)

                j += 1
            End While
            results.Add(group.ToList)
outer:
            i += 1
        End While
        Return results
    End Function

    Function CollectionToString(Of T)(c As IEnumerable(Of T)) As String
        Dim builder As New StringBuilder
        builder.Append("[")

        Dim it = c.GetEnumerator()
        If it.MoveNext() Then
            builder.Append(it.Current)
        End If
        While it.MoveNext()
            builder.Append(", ")
            builder.Append(it.Current)
        End While

        builder.Append("]")
        Return builder.ToString
    End Function

    Sub Main()
        Dim primes = Sieve(999999)
        Dim diffsList = {({2}), ({1}), ({2, 2}), ({2, 4}), ({4, 2}), ({6, 4, 2})}
        Console.WriteLine("For primes less than 1,000,000:-")
        Console.WriteLine()
        For Each diffs In diffsList
            Console.WriteLine("  For differences of {0} ->", CollectionToString(diffs))
            Dim sp = SuccessivePrimes(primes, diffs)
            If sp.Count = 0 Then
                Console.WriteLine("    No groups found")
                Continue For
            End If
            Console.WriteLine("    First group   = {0}", CollectionToString(sp(0)))
            Console.WriteLine("    Last group    = {0}", CollectionToString(sp(sp.Count - 1)))
            Console.WriteLine("    Number found  = {0}", sp.Count)
            Console.WriteLine()
        Next
    End Sub

End Module


  

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