How to resolve the algorithm Sudan function step by step in the C++ programming language
How to resolve the algorithm Sudan function step by step in the C++ programming language
Table of Contents
Problem Statement
The Sudan function is a classic example of a recursive function, notable especially because it is not a primitive recursive function. This is also true of the better-known Ackermann function. The Sudan function was the first function having this property to be published. The Sudan function is usually defined as follows (svg):
F
0
( x , y )
= x + y
F
n + 1
( x , 0 )
= x
if
n ≥ 0
F
n + 1
( x , y + 1 )
=
F
n
(
F
n + 1
( x , y ) ,
F
n + 1
( x , y ) + y + 1 )
if
n ≥ 0
{\displaystyle {\begin{array}{lll}F_{0}(x,y)&=x+y\F_{n+1}(x,0)&=x&{\text{if }}n\geq 0\F_{n+1}(x,y+1)&=F_{n}(F_{n+1}(x,y),F_{n+1}(x,y)+y+1)&{\text{if }}n\geq 0\\end{array}}}
Write a function which returns the value of F(x, y).
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Sudan function step by step in the C++ programming language
The provided C++ code defines a recursive function F
and demonstrates its usage in the main
function. Here's how the code works:
-
Function
F(int n, int x, int y)
:- This is a recursive function that takes three integer arguments:
n
,x
, andy
. - It uses if-else statements to handle different cases:
- If
n
is equal to 0, it returns the sum ofx
andy
. - If
y
is equal to 0, it returnsx
. - Otherwise, it makes two recursive calls to itself, one with
y
decremented by 1 and the other with bothx
andy
decremented by 1. It then returns the result of the second recursive call plusy
.
- If
- This is a recursive function that takes three integer arguments:
-
main
Function:- In the
main
function, the program callsF(1, 3, 3)
and prints the result.
- In the
Example Execution:
When you run this program, it will calculate and print the value of F(1, 3, 3)
.
- The recursive calls will proceed as follows:
F(1, 3, 3) -> F(0, F(1, 3, 2), F(1, 3, 2) + 2) -> F(0, F(1, 3, 1), F(1, 3, 1) + 1) -> ...
- Eventually, it will reach the base case where
n
ory
becomes 0 and will start returning values:F(0, 6, 6) -> 6
F(1, 6, 5) -> 11
F(1, 11, 4) -> 15
- The final result will be:
F(1, 3, 3) -> 15
- Therefore, it prints:
F(1,3,3) = 15
Source code in the cpp programming language
//Aamrun , 11th July, 2022
#include <iostream>
using namespace std;
int F(int n,int x,int y) {
if (n == 0) {
return x + y;
}
else if (y == 0) {
return x;
}
return F(n - 1, F(n, x, y - 1), F(n, x, y - 1) + y);
}
int main() {
cout << "F(1,3,3) = "<<F(1,3,3)<<endl;
return 0;
}
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