Problem Statement

The objective is to write a function that finds the sum of all positive multiples of 3 or 5 below n. Show output for n = 1000. This is is the same as Project Euler problem 1. Extra credit: do this efficiently for n = 1e20 or higher.

Let's start with the solution:

F sum35(limit)
   V sum = 0
   L(i) 1 .< limit
      I i % 3 == 0 | i % 5 == 0
         sum += i
   R sum

print(sum35(1000))