Step by Step solution about How to resolve the algorithm Sum of a series step by step in the Julia programming language

The source code is a snippet of Julia code that calculates the sum of the reciprocals of the squares of the first 1000 natural numbers. This sum is an approximation of the value of pi squared divided by 6, which is approximately 1.6449340668482264. The first line of code uses the sum function to calculate the sum of the reciprocals of the squares of the first 1000 natural numbers. The k -> 1/k^2 part of the code is a lambda function that takes a single argument, k, and returns the reciprocal of the square of k. The second line of code prints the value of pi squared divided by 6. The third and fourth lines of code define a function called f that takes a single argument, n, and returns the sum of the reciprocals of the squares of the first n natural numbers. The for loop in the function iterates over the values from 1 to n, and the s += 1/k^2 line of code adds the reciprocal of the square of k to the s variable. The last line of code calls the f function with the argument 1000, and prints the result.

julia> sum(k -> 1/k^2, 1:1000)
1.643934566681559

julia> pi^2/6
1.6449340668482264


julia> function f(n)
    s = 0.0
    for k = 1:n
      s += 1/k^2
    end
    return s
end

julia> f(1000)
1.6439345666815615