How to resolve the algorithm Sum of elements below main diagonal of matrix step by step in the ALGOL 68 programming language

Published on 12 May 2024 09:40 PM

How to resolve the algorithm Sum of elements below main diagonal of matrix step by step in the ALGOL 68 programming language

Table of Contents

Problem Statement

Find and display the sum of elements that are below the main diagonal of a matrix. The matrix should be a square matrix.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm Sum of elements below main diagonal of matrix step by step in the ALGOL 68 programming language

Source code in the algol programming language

BEGIN # sum the elements below the main diagonal of a matrix  #
    # returns the sum of the elements below the main diagonal #
    # of m, m must be a square matrix                         #
    OP   LOWERSUM = ( [,]INT m )INT:
         IF 1 LWB m /= 2 LWB m OR 1 UPB m /= 2 UPB m THEN
            # the matrix isn't square                         #
            print( ( "Matrix must be suare for LOWERSUM", newline ) );
            stop
         ELSE
            # have a square matrix                            #
            INT sum := 0;
            FOR r FROM 1 LWB m + 1 TO 1 UPB m DO
                 FOR c FROM 1 LWB m TO r - 1 DO
                     sum +:= m[ r, c ]
                 OD
            OD;
            sum
         FI; # LOWERSUM #
    # task test case                                          #
    print( ( whole( LOWERSUM [,]INT( (  1,  3,  7,  8, 10 )
                                   , (  2,  4, 16, 14,  4 )
                                   , (  3,  1,  9, 18, 11 )
                                   , ( 12, 14, 17, 18, 20 )
                                   , (  7,  1,  3,  9,  5 )
                                   )
                  , 0
                  )
            , newline
            )
          )
END

  

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