How to resolve the algorithm Summarize primes step by step in the Rust programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Summarize primes step by step in the Rust programming language
Table of Contents
Problem Statement
Considering in order of length, n, all sequences of consecutive primes, p, from 2 onwards, where p < 1000 and n>0, select those sequences whose sum is prime, and for these display the length of the sequence, the last item in the sequence, and the sum.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Summarize primes step by step in the Rust programming language
Source code in the rust programming language
// [dependencies]
// primal = "0.3"
fn main() {
let limit = 1000;
let mut sum = 0;
println!("count prime sum");
for (n, p) in primal::Sieve::new(limit)
.primes_from(2)
.take_while(|x| *x < limit)
.enumerate()
{
sum += p;
if primal::is_prime(sum as u64) {
println!(" {:>3} {:>3} {:>5}", n + 1, p, sum);
}
}
}
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