How to resolve the algorithm Sutherland-Hodgman polygon clipping step by step in the Tcl programming language
How to resolve the algorithm Sutherland-Hodgman polygon clipping step by step in the Tcl programming language
Table of Contents
Problem Statement
The Sutherland-Hodgman clipping algorithm finds the polygon that is the intersection between an arbitrary polygon (the “subject polygon”) and a convex polygon (the “clip polygon”). It is used in computer graphics (especially 2D graphics) to reduce the complexity of a scene being displayed by eliminating parts of a polygon that do not need to be displayed.
Take the closed polygon defined by the points: and clip it by the rectangle defined by the points: Print the sequence of points that define the resulting clipped polygon.
Display all three polygons on a graphical surface, using a different color for each polygon and filling the resulting polygon. (When displaying you may use either a north-west or a south-west origin, whichever is more convenient for your display mechanism.)
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Sutherland-Hodgman polygon clipping step by step in the Tcl programming language
Source code in the tcl programming language
# Find intersection of an arbitrary polygon with a convex one.
package require Tcl 8.6
# Does the path (x0,y0)->(x1,y1)->(x2,y2) turn clockwise
# or counterclockwise?
proc cw {x0 y0 x1 y1 x2 y2} {
set dx1 [expr {$x1 - $x0}]; set dy1 [expr {$y1 - $y0}]
set dx2 [expr {$x2 - $x0}]; set dy2 [expr {$y2 - $y0}]
# (0,0,$dx1*$dy2 - $dx2*$dy1) is the crossproduct of
# ($x1-$x0,$y1-$y0,0) and ($x2-$x0,$y2-$y0,0).
# Its z-component is positive if the turn
# is clockwise, negative if the turn is counterclockwise.
set pr1 [expr {$dx1 * $dy2}]
set pr2 [expr {$dx2 * $dy1}]
if {$pr1 > $pr2} {
# Clockwise
return 1
} elseif {$pr1 < $pr2} {
# Counter-clockwise
return -1
} elseif {$dx1*$dx2 < 0 || $dy1*$dy2 < 0} {
# point 0 is the middle point
return 0
} elseif {($dx1*$dx1 + $dy1*$dy1) < ($dx2*$dx2 + $dy2+$dy2)} {
# point 1 is the middle point
return 0
} else {
# point 2 lies on the segment joining points 0 and 1
return 1
}
}
# Calculate the point of intersection of two lines
# containing the line segments (x1,y1)-(x2,y2) and (x3,y3)-(x4,y4)
proc intersect {x1 y1 x2 y2 x3 y3 x4 y4} {
set d [expr {($y4 - $y3) * ($x2 - $x1) - ($x4 - $x3) * ($y2 - $y1)}]
set na [expr {($x4 - $x3) * ($y1 - $y3) - ($y4 - $y3) * ($x1 - $x3)}]
if {$d == 0} {
return {}
}
set r [list \
[expr {$x1 + $na * ($x2 - $x1) / $d}] \
[expr {$y1 + $na * ($y2 - $y1) / $d}]]
return $r
}
# Coroutine that yields the elements of a list in pairs
proc pairs {list} {
yield [info coroutine]
foreach {x y} $list {
yield [list $x $y]
}
return {}
}
# Coroutine to clip one segment of a polygon against a line.
proc clipsegment {inside0 cx0 cy0 cx1 cy1 sx0 sy0 sx1 sy1} {
set inside1 [expr {[cw $cx0 $cy0 $cx1 $cy1 $sx1 $sy1] > 0}]
if {$inside1} {
if {!$inside0} {
set int [intersect $cx0 $cy0 $cx1 $cy1 \
$sx0 $sy0 $sx1 $sy1]
if {[llength $int] >= 0} {
yield $int
}
}
yield [list $sx1 $sy1]
} else {
if {$inside0} {
set int [intersect $cx0 $cy0 $cx1 $cy1 \
$sx0 $sy0 $sx1 $sy1]
if {[llength $int] >= 0} {
yield $int
}
}
}
return $inside1
}
# Coroutine to perform one step of Sutherland-Hodgman polygon clipping
proc clipstep {source cx0 cy0 cx1 cy1} {
yield [info coroutine]
set pt0 [{*}$source]
if {[llength $pt0] == 0} {
return
}
lassign $pt0 sx0 sy0
set inside0 [expr {[cw $cx0 $cy0 $cx1 $cy1 $sx0 $sy0] > 0}]
set finished 0
while {!$finished} {
set thispt [{*}$source]
if {[llength $thispt] == 0} {
set thispt $pt0
set finished 1
}
lassign $thispt sx1 sy1
set inside0 [clipsegment $inside0 \
$cx0 $cy0 $cx1 $cy1 $sx0 $sy0 $sx1 $sy1]
set sx0 $sx1
set sy0 $sy1
}
return {}
}
# Perform Sutherland-Hodgman polygon clipping
proc clippoly {cpoly spoly} {
variable clipindx
set source [coroutine clipper[incr clipindx] pairs $spoly]
set cx0 [lindex $cpoly end-1]
set cy0 [lindex $cpoly end]
foreach {cx1 cy1} $cpoly {
set source [coroutine clipper[incr clipindx] \
clipstep $source $cx0 $cy0 $cx1 $cy1]
set cx0 $cx1; set cy0 $cy1
}
set result {}
while {[llength [set pt [{*}$source]]] > 0} {
lappend result {*}$pt
}
return $result
}
package require Tk
grid [canvas .c -width 400 -height 400 -background \#ffffff]
proc demonstrate {cpoly spoly} {
set rpoly [clippoly $cpoly $spoly]
puts $rpoly
.c create polygon $cpoly -outline \#ff9999 -fill {} -width 5
.c create polygon $spoly -outline \#9999ff -fill {} -width 3
.c create polygon $rpoly -fill \#99ff99 -outline black -width 1
}
demonstrate {100 100 300 100 300 300 100 300} \
{50 150 200 50 350 150 350 300 250 300 200 250 150 350 100 250 100 200}
You may also check:How to resolve the algorithm Assertions step by step in the ALGOL 68 programming language
You may also check:How to resolve the algorithm Greatest element of a list step by step in the CMake programming language
You may also check:How to resolve the algorithm Priority queue step by step in the Factor programming language
You may also check:How to resolve the algorithm Create a file step by step in the Little programming language
You may also check:How to resolve the algorithm Angle difference between two bearings step by step in the Quackery programming language