How to resolve the algorithm Symmetric difference step by step in the Ruby programming language
How to resolve the algorithm Symmetric difference step by step in the Ruby programming language
Table of Contents
Problem Statement
Given two sets A and B, compute
( A ∖ B ) ∪ ( B ∖ A ) .
{\displaystyle (A\setminus B)\cup (B\setminus A).}
That is, enumerate the items that are in A or B but not both. This set is called the symmetric difference of A and B. In other words:
( A ∪ B ) ∖ ( A ∩ B )
{\displaystyle (A\cup B)\setminus (A\cap B)}
(the set of items that are in at least one of A or B minus the set of items that are in both A and B). Optionally, give the individual differences (
A ∖ B
{\displaystyle A\setminus B}
and
B ∖ A
{\displaystyle B\setminus A}
) as well.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Symmetric difference step by step in the Ruby programming language
This code example shows how to find the symmetric difference between two arrays in Ruby. The symmetric difference between two sets is the set of elements which are in one of the sets, but not in both.
First approach:
The first approach uses the | and & operators to find the union and intersection of the two arrays, respectively.
The union of two sets is the set of all elements that are in either set, while the intersection of two sets is the set of all elements that are in both sets.
The symmetric difference can then be found by subtracting the intersection from the union.
a = ["John", "Serena", "Bob", "Mary", "Serena"]
b = ["Jim", "Mary", "John", "Jim", "Bob"]
# the union minus the intersection:
p sym_diff = (a | b)-(a & b) # => ["Serena", "Jim"]
Second approach:
The second approach uses the Set class to find the symmetric difference between the two arrays.
The Set class represents a mathematical set, which is a collection of unique elements.
The ^ operator can be used to find the symmetric difference between two sets.
require 'set'
a = Set["John", "Serena", "Bob", "Mary", "Serena"] #Set removes duplicates
b = Set["Jim", "Mary", "John", "Jim", "Bob"]
p sym_diff = a ^ b # => #<Set: {"Jim", "Serena"}>
Source code in the ruby programming language
a = ["John", "Serena", "Bob", "Mary", "Serena"]
b = ["Jim", "Mary", "John", "Jim", "Bob"]
# the union minus the intersection:
p sym_diff = (a | b)-(a & b) # => ["Serena", "Jim"]
require 'set'
a = Set["John", "Serena", "Bob", "Mary", "Serena"] #Set removes duplicates
b = Set["Jim", "Mary", "John", "Jim", "Bob"]
p sym_diff = a ^ b # => #<Set: {"Jim", "Serena"}>
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