Step by Step solution about How to resolve the algorithm Terminal control/Cursor movement step by step in the Kotlin programming language

Kotlin code

• Constants: a constant variable ESC is declared and initialized with the escape character \u001B.

• Main Function:

  • main function is the entry point of the program.
  • print("$ESC[2J"): clears the terminal screen.
  • print("$ESC[10;10H"): moves the cursor to the (10, 10) position on the screen.

• Array:

  • An array aecs of escape codes is defined. Each escape code represents a cursor movement:
    • [1D = left
    • [1C = right
    • [1A = up
    • [1B = down
    • [9D = line start
    • [H = top left
    • [24;79H = bottom right (assuming an 80x24 terminal)

• Movement Loop:

  • A for loop iterates through each escape code in aecs.
  • Inside the loop:
    • Thread.sleep(3000): pauses the program for three seconds between each cursor movement.
    • println("$ESC$aec"): prints the escape code, which causes the cursor to move.

• Final Pause:

  • After the loop finishes, the thread pauses for an additional three seconds with Thread.sleep(3000).
  • println() prints a newline character to return the cursor to the beginning of the next line.

Outcome: When you run this program, you'll see the cursor move around the terminal screen, following the specified cursor movements in the aecs array. Each movement is displayed for three seconds before the next one occurs.

// version 1.1.2

const val ESC = "\u001B"  // escape code

fun main(args: Array<String>) {
    print("$ESC[2J")     // clear terminal first
    print("$ESC[10;10H") // move cursor to (10, 10) say
    val aecs = arrayOf(
        "[1D",    // left
        "[1C",    // right
        "[1A",    // up
        "[1B",    // down
        "[9D",    // line start
        "[H",     // top left
        "[24;79H" // bottom right - assuming 80 x 24 terminal
    )
    for (aec in aecs) {
        Thread.sleep(3000) // three second display between cursor movements
        print("$ESC$aec")
    }
    Thread.sleep(3000)
    println()
}