Step by Step solution about How to resolve the algorithm Terminal control/Hiding the cursor step by step in the Julia programming language

The provided Julia code performs the following tasks:

1. Hide the cursor: It uses the escape code $ESC[?25l to hide the cursor on the terminal. This makes the cursor invisible to the user.

2. Prompt for input: It prints a message "Enter anything, press RETURN: " to prompt the user to enter some text.

3. Read input without visible cursor: It uses the readline() function to read a line of input from the user. However, since the cursor is hidden, the user will not see the cursor moving as they type.

4. Reset terminal: After the user presses RETURN and enters some text, it prints the escape code sequence $ESC[0H$ESC[0J$ESC[?25h to reset the terminal settings. This shows the cursor again, clears the screen, and returns the output cursor to the home position.

5. Wait 3 seconds: It uses sleep(3) to pause the execution of the code for 3 seconds, allowing the user to see the text they entered on the screen before it disappears.

6. Print a newline: Finally, it prints a newline character to create a visual separation between the entered text and any subsequent output from the program.

In summary, this code takes user input without showing the cursor, waits for a moment to display the input, and then resets the terminal settings to show the cursor again. It can be useful in situations where you want to prompt the user for sensitive data or where you want to hide the cursor to create a cleaner or more focused user experience.

const ESC = "\u001B" # escape code
print("$ESC[?25l")                       # hide the cursor
print("Enter anything, press RETURN: ")  # prompt shown
input = readline()                       # but no cursor 
print("$ESC[0H$ESC[0J$ESC[?25h")         # reset, visible again
sleep(3)
println()