How to resolve the algorithm The Name Game step by step in the V (Vlang) programming language
How to resolve the algorithm The Name Game step by step in the V (Vlang) programming language
Table of Contents
Problem Statement
Write a program that accepts a name as input and outputs the lyrics to the Shirley Ellis song "The Name Game".
The regular verse Unless your name begins with a vowel (A, E, I, O, U), 'B', 'F' or 'M' you don't have to care about special rules. The verse for the name 'Gary' would be like this: At the end of every line, the name gets repeated without the first letter: Gary becomes ary If we take (X) as the full name (Gary) and (Y) as the name without the first letter (ary) the verse would look like this: Vowel as first letter of the name If you have a vowel as the first letter of your name (e.g. Earl) you do not truncate the name. The verse looks like this: 'B', 'F' or 'M' as first letter of the name In case of a 'B', an 'F' or an 'M' (e.g. Billy, Felix, Mary) there is a special rule. The line which would 'rebuild' the name (e.g. bo-billy) is sung without the first letter of the name. The verse for the name Billy looks like this: For the name 'Felix', this would be right:
Let's start with the solution:
Step by Step solution about How to resolve the algorithm The Name Game step by step in the V (Vlang) programming language
Source code in the v programming language
fn main() {
list := ['Gary', 'Earl', 'Billy', 'Felix', 'Mary']
for name in list {verse(name)}
}
fn verse(name string) {
mut b, mut f, mut m, mut y :='','','',''
mut x := name.to_lower().title()
y = x.substr(1, x.len)
if 'AEIOU'.contains(x[0].ascii_str()) {y = x.to_lower()}
b = 'b' + y
f = 'f' + y
m = 'm' + y
match x[0].ascii_str() {
'B' {b = y}
'F' {f = y}
'M' {m = y}
else {}
}
println('$x, $x, bo-$b')
println('Banana-fana fo-$f')
println('Fee-fi-mo-$m')
println('$x!\n')
}
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