How to resolve the algorithm Tic-tac-toe step by step in the Fortran programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Tic-tac-toe step by step in the Fortran programming language
Table of Contents
Problem Statement
Play a game of tic-tac-toe. Ensure that legal moves are played and that a winning position is notified.
Tic-tac-toe is also known as:
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Tic-tac-toe step by step in the Fortran programming language
Source code in the fortran programming language
! This is a fortran95 implementation of the game of tic-tac-toe.
! - Objective was to use less than 100 lines.
! - No attention has been devoted to efficiency.
! - Indentation by findent: https://sourceforge.net/projects/findent/
! - This is free software, use as you like at own risk.
! - Compile: gfortran -o tictactoe tictactoe.f90
! - Run: ./tictactoe
! Comments to: wvermin at gmail dot com
module tic
implicit none
integer :: b(9)
contains
logical function iswin(p)
integer,intent(in) :: p
iswin = &
all(b([1,2,3])==p).or.all(b([4,5,6])==p).or.all(b([7,8,9])==p).or.&
all(b([1,4,7])==p).or.all(b([2,5,8])==p).or.all(b([3,6,9])==p).or.&
all(b([1,5,9])==p).or.all(b([3,5,7])==p)
end function iswin
subroutine printb(mes)
character(len=*) :: mes
integer :: i,j
character :: s(0:2) = ['.','X','O']
print "(3a3,' ',3i3)",(s(b(3*i+1:3*i+3)),(j,j=3*i+1,3*i+3),i=0,2)
if(mes /= ' ') print "(/,a)",mes
end subroutine printb
integer recursive function minmax(player,bestm) result(bestv)
integer :: player,bestm,move,v,bm,win=1000,inf=100000
real :: x
if (all(b .ne. 0)) then
bestv = 0
else
bestv = -inf
do move=1,9
if (b(move) == 0) then
b(move) = player
if (iswin(player)) then
v = win
else
call random_number(x)
v = -minmax(3-player,bm) - int(10*x)
endif
if (v > bestv) then
bestv = v
bestm = move
endif
b(move) = 0
if (v == win) exit
endif
enddo
endif
end function minmax
end module tic
program tictactoe
! computer: player=1, user: player=2
use tic
implicit none
integer :: move,ios,v,bestmove,ply,player=2,k,values(8)
integer,allocatable :: seed(:)
call date_and_time(values=values)
call random_seed(size=k)
allocate(seed(k))
seed = values(8)+1000*values(7)+60*1000*values(6)+60*60*1000*values(5)
call random_seed(put=seed)
mainloop: do
b = 0
call printb('You have O, I have X. You enter 0: game ends.')
plyloop: do ply=0,4
if (player == 2 .or. ply >0 ) then ! user move
write(*,"(/,a)",advance='no'),'Your move? (0..9) '
getloop: do
readloop: do
read (*,*,iostat=ios),move
if (ios == 0 .and. move >= 0 .and. move <= 9) exit readloop
write(*,"(a)",advance='no'),'huh? Try again (0..9): '
enddo readloop
if ( move == 0) exit mainloop
if (b(move) == 0) exit getloop
write(*,"(a)",advance='no'),'Already occupied, again (0..9): '
enddo getloop
b(move) = 2
if(iswin(2)) then ! this should not happen
call printb('***** You win *****')
exit plyloop
endif
endif
v = minmax(1,bestmove) ! computer move
b(bestmove) = 1
if(iswin(1)) then
call printb('***** I win *****')
exit plyloop
endif
write(*,"(/,a,i3)"), 'My move: ',bestmove
call printb(' ')
enddo plyloop
if(ply == 5) write(*,"('***** Draw *****',/)")
player = 3-player
enddo mainloop
end program
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