How to resolve the algorithm Tokenize a string with escaping step by step in the CLU programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Tokenize a string with escaping step by step in the CLU programming language
Table of Contents
Problem Statement
Write a function or program that can split a string at each non-escaped occurrence of a separator character. It should accept three input parameters:
It should output a list of strings. Rules for splitting:
Rules for escaping:
Demonstrate that your function satisfies the following test-case: (Print the output list in any format you like, as long as it is it easy to see what the fields are.)
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Tokenize a string with escaping step by step in the CLU programming language
Source code in the clu programming language
tokenize = iter (sep, esc: char, s: string) yields (string)
escape: bool := false
part: array[char] := array[char]$[]
for c: char in string$chars(s) do
if escape then
escape := false
array[char]$addh(part,c)
elseif c=esc then
escape := true
elseif c=sep then
yield(string$ac2s(part))
part := array[char]$[]
else
array[char]$addh(part,c)
end
end
yield(string$ac2s(part))
end tokenize
start_up = proc ()
po: stream := stream$primary_output()
testcase: string := "one^|uno||three^^^^|four^^^|^quatro|"
for part: string in tokenize('|', '^', testcase) do
stream$putl(po, "\"" || part || "\"")
end
end start_up
You may also check:How to resolve the algorithm Count in octal step by step in the Bracmat programming language
You may also check:How to resolve the algorithm String matching step by step in the Smalltalk programming language
You may also check:How to resolve the algorithm Find limit of recursion step by step in the Fermat programming language
You may also check:How to resolve the algorithm Comments step by step in the NESL programming language
You may also check:How to resolve the algorithm Binary digits step by step in the VBA programming language