How to resolve the algorithm Truncatable primes step by step in the Elixir programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm Truncatable primes step by step in the Elixir programming language
Table of Contents
Problem Statement
A truncatable prime is a prime number that when you successively remove digits from one end of the prime, you are left with a new prime number.
The number 997 is called a left-truncatable prime as the numbers 997, 97, and 7 are all prime. The number 7393 is a right-truncatable prime as the numbers 7393, 739, 73, and 7 formed by removing digits from its right are also prime. No zeroes are allowed in truncatable primes.
The task is to find the largest left-truncatable and right-truncatable primes less than one million (base 10 is implied).
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Truncatable primes step by step in the Elixir programming language
Source code in the elixir programming language
defmodule Prime do
defp left_truncatable?(n, prime) do
func = fn i when i<=9 -> 0
i -> to_string(i) |> String.slice(1..-1) |> String.to_integer end
truncatable?(n, prime, func)
end
defp right_truncatable?(n, prime) do
truncatable?(n, prime, fn i -> div(i, 10) end)
end
defp truncatable?(n, prime, trunc_func) do
if to_string(n) |> String.match?(~r/0/),
do: false,
else: trunc_loop(trunc_func.(n), prime, trunc_func)
end
defp trunc_loop(0, _prime, _trunc_func), do: true
defp trunc_loop(n, prime, trunc_func) do
if elem(prime,n), do: trunc_loop(trunc_func.(n), prime, trunc_func), else: false
end
def eratosthenes(limit) do # descending order
Enum.to_list(2..limit) |> sieve(:math.sqrt(limit), [])
end
defp sieve([h|_]=list, max, sieved) when h>max, do: Enum.reverse(list, sieved)
defp sieve([h | t], max, sieved) do
list = for x <- t, rem(x,h)>0, do: x
sieve(list, max, [h | sieved])
end
defp prime_table(_, [], list), do: [false, false | list]
defp prime_table(n, [n|t], list), do: prime_table(n-1, t, [true|list])
defp prime_table(n, prime, list), do: prime_table(n-1, prime, [false|list])
def task(limit \\ 1000000) do
prime = eratosthenes(limit)
prime_tuple = prime_table(limit, prime, []) |> List.to_tuple
left = Enum.find(prime, fn n -> left_truncatable?(n, prime_tuple) end)
IO.puts "Largest left-truncatable prime : #{left}"
right = Enum.find(prime, fn n -> right_truncatable?(n, prime_tuple) end)
IO.puts "Largest right-truncatable prime: #{right}"
end
end
Prime.task
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