How to resolve the algorithm URL decoding step by step in the ooRexx programming language

Published on 12 May 2024 09:40 PM
#Oorexx

How to resolve the algorithm URL decoding step by step in the ooRexx programming language

Table of Contents

Problem Statement

This task   (the reverse of   URL encoding   and distinct from   URL parser)   is to provide a function or mechanism to convert an URL-encoded string into its original unencoded form.

Let's start with the solution:

Step by Step solution about How to resolve the algorithm URL decoding step by step in the ooRexx programming language

Source code in the oorexx programming language

/* Rexx */
  X = 0
  url. = ''
  X = X + 1; url.0 = X; url.X = 'http%3A%2F%2Ffoo%20bar%2F'
  X = X + 1; url.0 = X; url.X = 'mailto%3A%22Ivan%20Aim%22%20%3Civan%2Eaim%40email%2Ecom%3E'
  X = X + 1; url.0 = X; url.X = '%6D%61%69%6C%74%6F%3A%22%49%72%6D%61%20%55%73%65%72%22%20%3C%69%72%6D%61%2E%75%73%65%72%40%6D%61%69%6C%2E%63%6F%6D%3E'

  Do u_ = 1 to url.0
    Say url.u_
    Say DecodeURL(url.u_)
    Say
    End u_

Exit

DecodeURL: Procedure

  Parse Arg encoded
  decoded = ''
  PCT = '%'

  Do label e_ while encoded~length() > 0
    Parse Var encoded head (PCT) +1 code +2 tail
    decoded = decoded || head
    Select
      when code~strip('T')~length() = 2 & code~datatype('X') then Do
        code = code~x2c()
        decoded = decoded || code
        End
      when code~strip('T')~length() \= 0 then Do
        decoded = decoded || PCT
        tail = code || tail
        End
      otherwise 
        Nop
      End
    encoded = tail
    End e_

  Return decoded

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