How to resolve the algorithm UTF-8 encode and decode step by step in the Forth programming language
Published on 12 May 2024 09:40 PM
How to resolve the algorithm UTF-8 encode and decode step by step in the Forth programming language
Table of Contents
Problem Statement
As described in UTF-8 and in Wikipedia, UTF-8 is a popular encoding of (multi-byte) Unicode code-points into eight-bit octets. The goal of this task is to write a encoder that takes a unicode code-point (an integer representing a unicode character) and returns a sequence of 1–4 bytes representing that character in the UTF-8 encoding. Then you have to write the corresponding decoder that takes a sequence of 1–4 UTF-8 encoded bytes and return the corresponding unicode character. Demonstrate the functionality of your encoder and decoder on the following five characters: Provided below is a reference implementation in Common Lisp.
Let's start with the solution:
Step by Step solution about How to resolve the algorithm UTF-8 encode and decode step by step in the Forth programming language
Source code in the forth programming language
: showbytes ( c-addr u -- )
over + swap ?do
i c@ 3 .r loop ;
: test {: xc -- :}
xc xemit xc 6 .r xc pad xc!+ pad tuck - ( c-addr u )
2dup showbytes drop xc@+ xc <> abort" test failed" drop cr ;
hex
$41 test $f6 test $416 test $20ac test $1d11e test
\ can also be written as
\ 'A' test 'ö' test 'Ж' test '€' test '𝄞' test
-77 Constant UTF-8-err
$80 Constant max-single-byte
: u8@+ ( u8addr -- u8addr' u )
count dup max-single-byte u< ?EXIT \ special case ASCII
dup $C2 u< IF UTF-8-err throw THEN \ malformed character
$7F and $40 >r
BEGIN dup r@ and WHILE r@ xor
6 lshift r> 5 lshift >r >r count
dup $C0 and $80 <> IF UTF-8-err throw THEN
$3F and r> or
REPEAT rdrop ;
: u8!+ ( u u8addr -- u8addr' )
over max-single-byte u< IF tuck c! 1+ EXIT THEN \ special case ASCII
>r 0 swap $3F
BEGIN 2dup u> WHILE
2/ >r dup $3F and $80 or swap 6 rshift r>
REPEAT $7F xor 2* or r>
BEGIN over $80 u>= WHILE tuck c! 1+ REPEAT nip ;
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