How to resolve the algorithm Variable-length quantity step by step in the Mathematica/Wolfram Language programming language
Published on 22 June 2024 08:30 PM
How to resolve the algorithm Variable-length quantity step by step in the Mathematica/Wolfram Language programming language
Table of Contents
Problem Statement
Implement some operations on variable-length quantities, at least including conversions from a normal number in the language to the binary representation of the variable-length quantity for that number, and vice versa. Any variants are acceptable.
With above operations,
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Variable-length quantity step by step in the Mathematica/Wolfram Language programming language
The provided Wolfram code handles conversions between integers and octet representations, where an octet is a sequence of eight bits.
toOctets[n]
- Converts an integer
n
into its octet representation as a string. - It uses
IntegerString
to convertn
to a hexadecimal string. - It partitions the string into groups of two characters each.
- If the length of the string is odd, a leading "0" is added to the first group.
- The resulting groups (octets) are joined back together to form the octet representation.
fromOctets[octets]
- Reverses the
toOctets
process, converting a list of octets back into an integer. - It joins all the octets into a single string.
- It converts the hexadecimal string to an integer using
FromDigits
.
Grid Usage
- The code demonstrates these functions by applying them to three different large integers:
16^^3ffffe
,16^^1fffff
, and16^^200000
. - It creates a grid where each row contains the integer, its octet representation, and the integer reconstructed from the octet representation.
Example:
Say we have the integer 16^^3ffffe
.
toOctets[16^^3ffffe]
gives{"03", "ff", "ff", "fe"}
as the octet representation.fromOctets[{"03", "ff", "ff", "fe"}]
successfully reconstructs the original integer16^^3ffffe
.
Source code in the wolfram programming language
toOctets[n_Integer] :=
StringJoin @@@
Partition[
PadLeft[Characters@IntegerString[n, 16],
2 Ceiling[Plus @@ DigitCount[n, 16]/2], {"0"}], 2]
fromOctets[octets_List] := FromDigits[StringJoin @@ octets, 16]
Grid[{#, toOctets@#, fromOctets[toOctets@#]} & /@ {16^^3ffffe, 16^^1fffff, 16^^200000}]
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