How to resolve the algorithm Variable size/Get step by step in the C++ programming language
Published on 7 June 2024 03:52 AM
How to resolve the algorithm Variable size/Get step by step in the C++ programming language
Table of Contents
Problem Statement
Demonstrate how to get the size of a variable. See also: Host introspection
Let's start with the solution:
Step by Step solution about How to resolve the algorithm Variable size/Get step by step in the C++ programming language
1. sizeof:
In C++, sizeof
is a unary operator that returns the size of the operand in bytes.
-
std::size_t intsize = sizeof(int);
: This line gets the size of anint
data type in bytes and stores it in a variable namedintsize
. -
std::size_t intbits = CHAR_BITS*sizeof(int);
: This line gets the number of bits in anint
data type, which isCHAR_BITS
(usually 8) multiplied by the size ofint
in bytes. It stores the result inintbits
.
2. sizeof(variable):
std::size_t a_size = sizeof a;
: This line gets the size of the variablea
, which is an integer, and stores it ina_size
. It's useful when you need to pass the size of an array or structure to a function.
3. sizeof(expression):
std::size_t size = sizeof (3*6 + 7.5);
: This line calculates the size of an expression(3*6 + 7.5)
, which is the size of the result type, which is a double in this case (8 bytes on most platforms). It stores the result insize
.
Source code in the cpp programming language
#include <cstdlib>
std::size_t intsize = sizeof(int);
#include <climits>
#include <cstdlib>
std::size_t intbits = CHAR_BITS*sizeof(int);
#include <cstdlib>
int a = 1;
std::size_t a_size = sizeof a;
#include <cstdlib>
std::size_t size = sizeof (3*6 + 7.5);
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